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3 years ago

What is the name of the compound PbS2 • 4H2O?

1 answer:

6 0

The name of the compound PbS2.4H2O would be hydrate of Lead(IV) sulfide. <span>The IV is to show that the lead in the </span>compound<span> has an oxidation state of +4. Lead also has an oxidation state of +2. Hope this answers the question. Have a nice day.</span>

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Nata [24]

Oregon trail would be the best answer

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4 years ago

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What is a biotic factor, and a an abiotic factor

statuscvo [17]

Explanation:

biotic factors are the things which have life like animals and plants

And Abiotic factors are the things which don't have life like air,stone and river

3 0

3 years ago

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The rate constant for the second-order reaction 2NOBr(g) ¡ 2NO(g) 1 Br2(g) is 0.80/M ? s at 108C. (a) Starting with a concentrat

Valentin [98]

Answer:

(a)

$0.0342M$

(b)

$t_{1/2}=17.36s\\t_{1/2}=23.15s$

Explanation:

Hello,

(a) In this case, as the reaction is second-ordered, one uses the following kinetic equation to compute the concentration of NOBr after 22 seconds:

$\frac{1}{[NOBr]}=kt +\frac{1}{[NOBr]_0}\\\frac{1}{[NOBr]}=\frac{0.8}{M*s}*22s+\frac{1}{0.086M}=\frac{29.3}{M}\\$

$[NOBr]=\frac{1}{29.2/M}=0.0342M$

(b) Now, for a second-order reaction, the half-life is computed as shown below:

$t_{1/2}=\frac{1}{k[NOBr]_0}$

Therefore, for the given initial concentrations one obtains:

$t_{1/2}=\frac{1}{\frac{0.80}{M*s}*0.072M}=17.36s\\t_{1/2}=\frac{1}{\frac{0.80}{M*s}*0.054M}=23.15s$

Best regards.

8 0

3 years ago

Read 2 more answers

The specific heat capacity of liquid water is 4.18 J/g oC. Calculate the quantity of energy required to heat 1.50 g of water fro

natima [27]

Answer: The quantity of heat required is 358.644 J.

Explanation:

Given: Specific heat capacity = $4.18 J/g^{o}C$

Mass = 1.50 g

$T_{1} = 26.5^{o}C$

$T_{2} = 83.7^{o}C$

Formula used to calculate heat energy is as follows.

$q = m \times C \times (T_{2} - T_{1})$

where,

q = heat energy

m = mass

C = specific heat capacity

$T_{1}$ = initial temperature

$T_{2}$ = final temperature

Substitute the values into above formula as follows.

$q = m \times C \times (T_{2} - T_{1})\\= 1.50 \times 4.18 J/g^{o}C \times (83.7 - 26.5)^{o}C\\= 358.644 J$

Thus, we can conclude that quantity of heat required is 358.644 J.

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3 years ago

Why is there such a large jump and ionization energy between the second and third ionization energy‘s for magnesium?

Romashka [77]

The second ionization energy of Mg is larger than the first because it always takes more energy to remove an electron from a positively charged ion than from a neutral atom. The third ionization energy of magnesium is enormous, however, because the Mg2+ ion has a filled-shell electron configuration.

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3 years ago