Answer:
N₂O₅
Explanation:
From the question given above, the following data were obtained:
Mass of compound = 7.546 g
Mass of nitrogen (N) = 1.957 g
Empirical formula =?
Next, we shall determine the mass of oxygen present in the compound. This can be obtained as follow:
Mass of compound = 7.546 g
Mass of nitrogen (N) = 1.957 g
Mass of Oxygen (O) =?
Mass of O = (Mass of compound) – (Mass of N)
Mass of O = 7.546 – 1.957
Mass of O = 5.589 g
Finally, we shall determine the empirical formula of the compound. This can be obtained as follow:
Mass of nitrogen (N) = 1.957 g
Mass of oxygen (O) = 5.589 g
Divide by their molar mass
N = 1.957 / 14 = 0.14
O = 5.589 / 16 = 0.35
Divide by the smallest
N = 0.140 / 0.14 = 1
O = 0.35 / 0.14 = 2.5
Multiply through by 2 to express in whole number
N = 1 × 2 = 2
O = 2.5 × 2 = 5
The empirical formula of the compound is N₂O₅.
