Answer: avogadros number/constant
Explanation:
Missing question: A possible atomic weight of Q is?
A)12.7.
B)19.0.
C)27.5
D)38.0
E)57.0.
Answer is: possible atomic weight of Q is B) 19.0.
Molecular weight of first molecule is 38.0 g/mol.
Molecular weight of second molecule is 57.0 g/mol.
Molecular weight of third molecule is 76.0 g/mol.
Molecular weight of fourth molecule is 114.0 g/mol.
All four molecular weights can be division only by 19 to get whole number:
Molecule 1 (38 ÷ 19 = 2), molecule 2 (57 ÷ 19 = 3), molecule 3 (76 ÷ 19 = 4) and molecule 4 ( 114 ÷ 19 = 6).
Molecular formulas are than Q₂, Q₃, Q₄ and Q₆.
Molecular weight of m is 40g. Hence, name of element m is Calcium. which is represented by the symbol Ca.
Given,
Moles of metal M = 0.300 moles
weight of mF₂ formed =23.4g
we have to find the name of element m...
Now,
m + F₂ → mF₂
1 mole of m reacts with 1 mole of F₂ (or 2 molecule of flourine) to form 1 mole of mF₂
Hence,
0.300 moles of m reacts with 0.300 moles of F₂ to form 0.300 moles of mF₂.
Hence,
23.4 g = 0.300 moles of mf2
0.300 × 38g + 0.300 × m = 23.4 g
Hence
m = 40 g
So, molecular weight of m is 40g. Hence, name of element m is Calcium. which is represented by the symbol Ca.
Thus, from the above conclusion we can say that, name of element m is Calcium. which is represented by the symbol Ca.
Learn more about Calcium here:brainly.com/question/26636816
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Answer:be careful and relax
Explanation:
Answer: 5.185
Explanation: The sum for 1.55 + 0.235 + 3.4 = 5.185
