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3 years ago

Can someone help me with this please!

Chemistry

1 answer:

Kryger [21]3 years ago

8 0

Step 1: Convert the given amount to moles, by dividing the given amount by the molecular weight of the compound.

5 g C3H8 (1 mol / 44 g C3H8) = 0.114 mol C3H8

Step 2: Find the mole ratio between the given and the desired target (in this case water). The mole ratio between C3H8 and water is 1:4, that is, you can make 4 times as much water from a one C3H8 (assuming that it isn't the limiting reactant).

0.114 mol C3H8 (4 moles H2O / 1 mol C3H8) = 0.456 mol H2O

Step 3: Reconvert back to grams by multiplying by the molecular weight of the new target (water).

0.456 mol H2O (18 g / 1 mol H2O) = 8.208 g Water. Hope this helped! :)

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Oksanka [162]

Answer:

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Explanation:

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2 years ago

How many moles are present in 54.8 mL of mercury if the density of mercury is 13.6 g/mL?

lesya692 [45]

Answer:

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General Formulas and Concepts:

Chemistry - Atomic Structure

Reading a Periodic Table
Using Dimensional Analysis
Density = Mass over Volume

Explanation:

Step 1: Define

D = 13.6 g/mL

54.8 mL Hg

Step 2: Identify Conversions

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Step 3: Find

13.6 g/mL = x g / 54.8 mL

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$745.28 \ g \ Hg(\frac{1 \ mol \ Hg}{200.59 \ g \ Hg} )$ = 3.71544 mol Hg

Step 5: Check

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Answer:

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