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2 years ago

Can someone help me with this please!

Chemistry

1 answer:

Kryger [21]2 years ago

8 0

<span>Step 1: Convert the given amount to moles, by dividing the given amount by the molecular weight of the compound.

5 g C3H8 (1 mol / 44 g C3H8) = 0.114 mol C3H8

Step 2: Find the mole ratio between the given and the desired target (in this case water). The mole ratio between C3H8 and water is 1:4, that is, you can make 4 times as much water from a one C3H8 (assuming that it isn't the limiting reactant).

0.114 mol C3H8 (4 moles H2O / 1 mol C3H8) = 0.456 mol H2O

Step 3: Reconvert back to grams by multiplying by the molecular weight of the new target (water).

0.456 mol H2O (18 g / 1 mol H2O) = 8.208 g Water. Hope this helped! :) </span><span />

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The concentrated sulfuric acid we use in the laboratory is 98.0% sulfuric acid by weight. Calculate the molality and molarity of

timama [110]

Answer : The molarity and molality of the solution is, 18.29 mole/L and 499.59 mole/Kg respectively.

Solution : Given,

Density of solution = $1.83g/cm^3=1.83g/ml$

Molar mass of sulfuric acid (solute) = 98.079 g/mole

98.0 % sulfuric acid by mass means that 98.0 gram of sulfuric acid is present in 100 g of solution.

Mass of sulfuric acid (solute) = 98.0 g

Mass of solution = 100 g

Mass of solvent = Mass of solution - Mass of solute = 100 - 98.0 = 2 g

First we have to calculate the volume of solution.

$\text{Volume of solution}=\frac{\text{Mass of solution}}{\text{Density of solution}}=\frac{100g}{1.83g/ml}=54.64ml$

Now we have to calculate the molarity of solution.

$Molarity=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{volume of solution}}=\frac{98.0g\times 1000}{98.079g/mole\times 54.64ml}=18.29mole/L$

Now we have to calculate the molality of the solution.

$Molality=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Mass of solvent}}=\frac{98.0g\times 1000}{98.079g/mole\times 2g}=499.59mole/Kg$

Therefore, the molarity and molality of the solution is, 18.29 mole/L and 499.59 mole/Kg respectively.

7 0

2 years ago

What is the weighted average of a nail in the sample data given?

Natalka [10]

The weighted average of the nail in accordance with the given data is 11.176g.

<h3>How to calculate weighted average?</h3>

Weighted average is an arithmetic mean of values biased according to agreed weightings.

The weighted average of the nail in the image above can be calculated by multiplying the decimal abundance with the mass of the nail, then summed up as follows;

Weighted average = (decimal abundance × mass 1) + (decimal abundance × mass 2)

Weighted average = (0.12 × 3.3) + (0.88 × 12.25)

Weighted average = 0.396 + 10.78

Weighted average = 11.176g

Therefore, 11.176g is the weighted average of the nail

Learn more about weighted average at: brainly.com/question/28042295

#SPJ1

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10 months ago

If a plane travels at a speed of 600 km/h, how long<br> would it take to travel a distance of 300 km

iogann1982 [59]

Answer:

30 minutes

Explanation:

If the plane is going 600 km/h

divide the length and time and it would be half of that, so 300 km would take 30 mins.

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3 years ago

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What is 155.4g÷8.70mL, rounded to the correct number of significant figures

OLEGan [10]

Answer:

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2 years ago

Identify which one of the three methods of analysis (i.e., TLC, IR and melting point) provides information about the structure o

Alex787 [66]

Answer:

IR provides structural information about a molecule. TLC and melting point analysis do not provide structural information.

Explanation:

IR gives information about the functional groups present in a molecule. The vibrational frequency of each functional group gives information about the structure of the entire molecule.

Structural features of a molecule are deduced by matching the vibrational frequencies of groups obtained from the IR spectroscopy with that of known functional groups in literature.

Melting point is a qualitative method that can only yield information about the identity of a compound and not its structure. Each compound has its unique melting point recorded in literature and any pure sample of the same compound must have the same sharp meting point.

Thin-layer chromatography (TLC) is a chromatography technique used to separate non-volatile mixtures. After separating the components of the mixture, it does not give any information regarding the identity or the structure of the components of the mixture.

Therefore, only IR yields structural information about a sample.

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