Atomic radii increase when going down a group and decreases when going towards the anion periods. So A and D.
Answer:
212.5 mL
both the original and the diluted solution have 0.765 moles of KCl
Explanation:
c1V1 = c2V2
V2 = c1V1/c2 = (1.8 M×425 mL)/1.2 M = 637.5 mL
(637.5 - 425) mL = 212.5 mL
n = (1.8 mol/L)(0.425 L) = 0.765 moles of KCl
since it's a dilution, the diluted solution has the same number of moles as the original solution, 0.765 moles of KCl
0.250 L*3M=0.250 L*3mol/L= 0.750 mol
Answer:
it's either B. or C.. hope this helps!
Explanation:
