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3 years ago

Described the test for carbon dioxide. Give the result of the test.

Chemistry

1 answer:

diamong [38]3 years ago

8 0

The test is detecting the gas through its reaction with lime water and the result so that the limewater will turn milky/cloudy

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Which step of the scientific method involves making an inference?

maria [59]

The only logical answer would be to D) draw a conclusion, given that an inference is another word for conclude. Helpful tip, if you are dealing with the scientific method just google the method and boom! there is your answer.

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3 years ago

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What is true about energy in an ordinary chemical reaction? Energy is... a- created b- destroyed c-not a or b d-used up by react

kap26 [50]

Energy cannot be created or destroyed, so the answer would be c.) not a or b.

Hope this helps!

6 0

3 years ago

500. ml of a solution containing 1. 5 m nh4cl(aq) is mixed with 500. ml of a solution containing 0. 50m of naoh(aq). what is the

Sladkaya [172]

The pH of the solution is determined by the hydrogen ion concentration. The pH of the solution with 1.5 M NH4Cl and 0.50 M NaOH is 8.77.

The potential of the hydrogen ion in the given solution is called pH which determines the acidity and basicity of the solution.

Given

The molar concentration of 500 mL NH4Cl = 1.5 M

The molar concentration of 500 mL NaOH= 0.50 M

Kb (NH3) = 1.8 × 10 -5

First pOH is calculated as,

pOH = pKB + log [NH4Cl][NaOH]

= - log 1.8 × 10-5 + log [1.5][0.50]

= - log 1.8 × 10-5 + log [3]

= 4.744 + 0.477

= 5.221

Now, pH is calculated from pOH as,

pH + pOH = 14

pH = 14 – pOH

= 14 – 5.221

= 8.77

Thus we found that, 8.77 is the pH of the solution with 1.5 M NH4Cl and 0.50 M NaOH.

learn more about pH:

brainly.com/question/12942138

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2 years ago

What is an example of a colloid?<br> A. Soda<br> B.Fog<br> C.Jewelry<br> D.Silverware

Olegator [25]

Answer:

the current answer is

silverware

4 0

4 years ago

Read 2 more answers

The osmotic pressure of an aqueoussolution of urea at 300 K is

den301095 [7]

<u>Answer:</u> The freezing point of solution is -0.09°C

<u>Explanation:</u>

To calculate the concentration of solute, we use the equation for osmotic pressure, which is:

$\pi=imRT$

where,

$\pi$ = osmotic pressure of the solution = 120 kPa

i = Van't hoff factor = 1 (for non-electrolytes)

m = concentration of solute in terms of molality = ?

R = Gas constant = $8.31\text{L kPa }mol^{-1}K^{-1}$

T = temperature of the solution = 300 K

Putting values in above equation, we get:

$120kPa=1\times m\times 8.31\text{ L kPa }mol^{-1}K^{-1}\times 300K\\\\m=0.05m$

To calculate the depression in freezing point, we use the equation:

$\Delta T=i\times K_f\times m$

where,

i = Vant hoff factor = 1 (for non-electrolytes)

$K_f$ = molal freezing point depression constant = 1.86°C/m

m = molality of solution = 0.05 m

Putting values in above equation, we get:

$\Delta T=1\times 1.86^oC/m\times 0.05m\\\\\Delta T=0.09^oC$

Depression in freezing point is defined as the difference in the freezing point of water and freezing point of solution.

The equation used to calculate freezing point of solution is:

$\Delta T=\text{freezing point of water}-\text{freezing point of solution}$

where,

$\Delta T$ = Depression in freezing point = 0.09 °C

Freezing point of water = 0°C

Freezing point of solution = ?

Putting values in above equation, we get:

$0.09^oC=0^oC-\text{Freezing point of solution}\\\\\text{Freezing point of solution}=-0.09^oC$

Hence, the freezing point of solution is -0.09°C

4 0

3 years ago