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2 years ago

What is the pH of the solution in which the [H+] is 1.0 × 10–4 mol/L ?

1 answer:

5 0

PH is a simplified observation of the acidity of a solution, defined as the -log [H+] (negative logarithm of the hydrogen concentration).

-log[10^-4] = 4

The pH of this solution is 4.

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Determine the volume occupied by 2.5 mol of a gas at 18 °C if the pressure is 81.8 kPa?

mars1129 [50]

Answer:

74 litre

Explanation:

using ideal gas eqation PV=nRT

here P(pressure)=81.8 kPa =81.8×10^3 Pa

moles=2.5

temperature=273.15+18=291.15K

Gas constant R=8.314m^3-Pa/K-mol

now, V=nRT/P = 8.314×2.5×291.5/81.8×10^3 ≈74litre

✌️;)

3 0

3 years ago

If a chlor-alkali cell used a current of 3X10⁴A, how many pounds of Cl₂ would be produced in a typical 8-h operating day?

vova2212 [387]

7 × 10² pounds of Cl₂ would be produced in a typical 8-h operating day.

<h3>What is Stoichiometry ?</h3>

Stoichiometry helps us use the balanced chemical equation to measures quantitative relationships and it is to calculate the amount of products and reactants that are given in a reaction.

<h3>What is Balanced chemical equation ?</h3>

The balanced chemical equation is the equation in which the number of atoms on the reactants side is equal to the number of atoms on the product side in an equation.

2Cl⁻ (aq) → Cl (g) + 2e⁻

According to stoichiometry, moles of Cl₂

$= (3 \times 10^4\ A) \left (\frac{\frac{C}{s}}{A} \right ) \left (\frac{3600\ s}{h} \right ) (8h) \left (\frac{1\ \text{mol}\ e^{-}}{9.65 \times 10^4\ C} \right ) \left (\frac{1\ \text{mol}\ Cl_2}{2\ \text{mol}\ e^-} \right )$

= 4477 moles

Pounds Cl₂

$= (4477\ \text{moles}\ Cl_2) \left (\frac{70.90\ g\ Cl_2}{\text{mol}} \right ) \left (\frac{1\ kg}{1000\ g} \right ) \left (\frac{2.205\ lb}{1\ kg} \right )$

= 7 × 10² lb

Thus from the above conclusion we can say that 7 × 10² pounds of Cl₂ would be produced in a typical 8-h operating day.

Learn more about Stoichiometry here: brainly.com/question/14935523

#SPJ4

5 0

1 year ago

Hydrazine (N2H4), a rocket fuel , reacts with oxygen to form nitrogen gas and water vapor. The reaction is represented with the

lilavasa [31]

Answer:

D) 8.40 L H₂O(g).

Explanation:

The balanced equation for the mentioned reaction is:

It is clear that 2.0 moles of N₂H₄ react with 1.0 mole of O₂ to produce 2.0 moles of N₂ and 2.0 moles of H₂O.

At STP, 4.20L of O₂ reacts with N₂H₄:

It is known that at STP: every 1.0 mol of any gas occupies 22.4 L.

<u>using cross multiplication: </u>

1.0 mol of O₂ represents → 22.4 L.

??? mol of O₂ represents → 4.2 L.

∴ 4.2 L of O₂ represents = (1.0 mol)(4.2 L)/(22.4 L) = 0.1875 mol.

To find the no. of moles of H₂O produced:

Using cross multiplication:

1.0 mol of O₂ produce → 2.0 mol of H₂O, from stichiometry.

0.1875 mol of O₂ produce → ??? mol of H₂O.

∴ The no. of moles of H₂O = (2.0 mol)(0.1875 mol)/(1.0 mol) = 3.75 mol.

Again, using cross multiplication:

1.0 mol of H₂O represents → 22.4 L, at STP.

3.75 mol of H₂O represents → ??? L.

<em>∴ The no. of liters of water vapor will be produced </em>= (3.75 mol)(22.4 L)/(1.0 mol) = <em>8.4 L.</em>

<em>So, the right choice is: D) 8.40 L H₂O(g).</em>

3 0

2 years ago

An atom has three full orbitals in its second energy level.

ICE Princess25 [194]

Orbitals am only hold two electrons each, so 3 orbitals can hold 6 electrons

7 0

3 years ago

Read 2 more answers

Balancing chemical equations

kolbaska11 [484]

Answer:

2B2 + 3O2 → 2B2O3

Explanation:

Balance The Equation: B2 + O2 = B2O3

1. Label Each Compound With a Variable

aB2 + bO2 = cB2O3

2. Create a System of Equations, One Per Element

B: 2a + 0b = 2c

O: 0a + 2b = 3c

3. Solve For All Variables (using substitution, gauss elimination, or a calculator)

a = 2

b = 3

c = 2

4. Substitute Coefficients and Verify Result

2B2 + 3O2 = 2B2O3

L R

B: 4 4 ✔️

O: 6 6 ✔️

hope this helps!

7 0

2 years ago