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QveST [7]
3 years ago
5

If the sea floor is spreading,why is the Earth not getting bigger?

Chemistry
2 answers:
TEA [102]3 years ago
4 0
Because the the sand on the sea for is very compact and the water salt and chemicals make it compact making it stick together and fill up holes or cracks before going anyhere
Marrrta [24]3 years ago
4 0
Well... there actually are areas of the seafloor that are spreading due to tectonic plates moving apart, but there are also places where these plates meet and one slides under the other (subduction zones) as a result, the earth is not getting bigger since these two actions cancel each other out. If that makes any sense.

That’s what I do know, but if you happen to need extra information, please let me know and I can go research it.
Have a great evening!
~Brooke❤️
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A gas at constant volume has a pressure of 4. 50 atm at 200. K. What will be the pressure of the gas at 250. K? 3. 60 atm 4. 60
Trava [24]

5.625 atm will be the pressure of the gas at 250 K temperature of the gas at constant volume.

<h3>How we calculate the pressure of the gas?</h3>

Pressure of the gas will be calculated by using the ideal gas equation as:

PV = nRT,

From the question, it is clear that:

Moles of the gas and volume is constant here, so we calculate the pressure by rearranging the above equation as:

P/T = nR/V

And required equation will be:

P₁/T₁ = P₂/T₂, where

P₁ = pressure of gas = 4.50 atm

T₁ = temperature of gas = 200 K

P₂ = pressure of gas = to find?

T₂ = temperature of gas = 250 K

On putting all these values in the above equation, we get

P₂ = 4.50 × 250 / 200 = 5.625 atm

Hence, 5.625 atm is the pressure of the gas.

To know more about ideal gas equation, visit the below link:

brainly.com/question/1056445

5 0
2 years ago
Agar is used to culture bacteria and as a medium in electrophoresis. The agar used in this Petri dish is a by-product of an unli
Ymorist [56]
Agar is extracted from an algae (agarophytes, <span>belong to the </span>Rhodophyta (red algae) phylum, <span>primarily from the </span>genera Gelidium<span> and </span><span>Gracilaria</span>).
Agar <span>or </span>agar-agar is a jelly-like substance. Agar is the mixture of two components, agaropectin (D-glucuronic acid and pyruvic acid) and <span>the polysaccharide agarose.</span>
4 0
3 years ago
If I have 340 mL of a 1.5 M NaBr solution, what will the concentration be if I add 560 mL more water to it?
ipn [44]

Answer:

0.5667 M ≅ 0.57 M.

Explanation:

It is known that the no. of millimoles of a solution before dilution is equal to the no. of millimoles of the solution after the dilution.

It can be expressed as:

(MV) before dilution = (MV) after dilution.

M before dilution = 1.5 M, V before dilution = 340 mL.

M after dilution = ??? M, V after dilution = 340 mL + 560 mL = 900 mL.

∴ M after dilution = (MV) before dilution/(V) after dilution = (1.5 M)(340 mL)/(900 mL) = 0.5667 M ≅ 0.57 M.

5 0
2 years ago
When the following redox equation is balanced with smallest whole number coefficients, the coefficient for nitrogen dioxide will
Phoenix [80]

In a redox reaction, electron could be lost or gained. The coefficients in the balanced redox reaction are;  1/2, 5, 1, 5, 2, 1.

<h3>What is a redox reaction equation?</h3>

A redox reaction equation shows the species that were oxidized or reduced in a redox reaction. In this case, we are asked for the coefficients in a balanced redox reaction equation.

We must recall that five electrons were lost/gained in the process hence the balanced reaction equation is;

1/2I2 + 5HNO3 -----> IO3^- + 5NO2 + 2H2O + H^+

The coefficients in the balanced equation therefore are; 1/2, 5, 1, 5, 2, 1.

Learn more about redox reaction: brainly.com/question/13293425

7 0
2 years ago
Read 2 more answers
How many grams of F are in 12.56 g of SF6? h.
natali 33 [55]

Answer:

9.80 g

Explanation:

The molecular mass of the atoms mentioned in the question is as follows -

S = 32 g / mol

F = 19 g / mol

The molecular mass of the compound , SF₆ = 32 + ( 6 * 19 ) = 146 g / mol

The mass of 6 F = 6 * 19 = 114 g /mol .

The percentage of F in the compound =

mass of 6 F / total mass of the compound * 100

Hence ,  

The percentage of F in the compound = 114 g /mol  / 146 g / mol * 100

78.08 %

Hence , from the question ,

In 12.56 g of the compound ,

The grams of F = 0.7808 * 12.56 = 9.80 g

4 0
3 years ago
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