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Masteriza [31]
3 years ago
15

The atomic mass of calcium is 40.08. What is the mass of 6.02 × 1023 atoms of calcium?

Chemistry
2 answers:
Bezzdna [24]3 years ago
5 0
The atomic mass given on the periodic table is the mass of one mole of the element (relative to the mass of 1/12 of carbon 12.) There are 6.022 x10^23 molecules of any atoms in a mole. Therefore when it asks for the mass of 6.02 x 10^23 atoms it's asking what is the mass of one mole of Calcium.

The answer, therefore, is 40.08 as it states the atomic mass of calcium is 40.08 
nordsb [41]3 years ago
3 0
It should be 40.08 grams...because the atomic mass is equivalent to 1 mole of atoms of an element in grams, and 6.023 × 10^23 atoms of calcium is the same as 1 mole of calcium.

Hope this helps!
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Determine the rate law, including the values of the orders and rate law constant, for the following reaction using the experimen
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Answer: Rate law=k[A]^1[B]^2, order with respect to A is 1, order with respect to B is 2 and total order is 3. Rate law constant is 3L^2mol^{-2}s^{-1}

Explanation: Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

Rate=k[A]^x[B]^y

k= rate constant

x = order with respect to A

y = order with respect to A

n = x+y = Total order

a) From trial 1: 1.2\times 10^{-2}=k[0.10]^x[0.20]^y    (1)

From trial 2: 4.8\times 10^{-2}=k[0.10]^x[0.40]^y    (2)

Dividing 2 by 1 :\frac{4.8\times 10^{-2}}{1.2\times 10^{-2}}=\frac{k[0.10]^x[0.40]^y}{k[0.10]^x[0.20]^y}

4=2^y,2^2=2^y therefore y=2.

b) From trial 2: 4.8\times 10^{-2}=k[0.10]^x[0.40]^y    (3)

From trial 3: 9.6\times 10^{-2}=k[0.20]^x[0.40]^y   (4)

Dividing 4 by 3:\frac{9.6\times 10^{-2}}{4.8\times 10^{-2}}=\frac{k[0.20]^x[0.40]^y}{k[0.10]^x[0.40]^y}

2=2^x,2=2^1, x=1

Thus rate law is Rate=k[A]^1[B]^2

Thus order with respect to A is 1 , order with respect to B is 2 and total order is 1+2=3.

c) For calculating k:

Using trial 1:  1.2\times 10^{-2}=k[0.10]^1[0.20]^2

k=3 L^2mol^{-2}s^{-1}.



6 0
3 years ago
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