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3 years ago

The atomic mass of calcium is 40.08. What is the mass of 6.02 × 1023 atoms of calcium?

2 answers:

5 0

The atomic mass given on the periodic table is the mass of one mole of the element (relative to the mass of 1/12 of carbon 12.) There are 6.022 x10^23 molecules of any atoms in a mole. Therefore when it asks for the mass of 6.02 x 10^23 atoms it's asking what is the mass of one mole of Calcium.

The answer, therefore, is 40.08 as it states the atomic mass of calcium is 40.08

nordsb [41]3 years ago

3 0

It should be 40.08 grams...because the atomic mass is equivalent to 1 mole of atoms of an element in grams, and 6.023 × 10^23 atoms of calcium is the same as 1 mole of calcium.

Hope this helps!

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$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$ .....(1)

Molarity of oxalic acid solution = 0.1255 M

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Putting values in equation 1, we get:

$0.100M=\frac{\text{Moles of oxalic acid}}{0.600L}\\\\\text{Moles of oxalic acid}=(0.100mol/L\times 0.600L)=0.06mol$

For the given chemical reaction:

$Fe_2O_3(s)+6H_2C_2O_4(aq.)\rightarrow 2Fe(C_2O_4)_3^{3-}(aq.)+3H_2O(l)+6H^+(aq.)$

By Stoichiometry of the reaction:

6 moles of oxalic acid reacts with 1 mole of ferric oxide (rust)

So, 0.06 moles of oxalic acid will react with = $\frac{1}{6}\times 0.06=0.01mol$ of ferric oxide (rust)

To calculate the mass of rust for given number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Molar mass of rust (ferric oxide) = 159.7 g/mol

Moles of rust = 0.01 moles

Putting values in above equation, we get:

$0.01mol=\frac{\text{Mass of rust}}{159.7g/mol}\\\\\text{Mass of rust}=(0.01mol\times 159.7g/mol)=1.597g$

Hence, the mass of rust that can be removed is 1.597 grams

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