Answer:
And the best option would be:
c. 1450 +/- 12
Step-by-step explanation:
Information provided
represent the sample mean for the SAT scores
population mean (variable of interest)
represent the sample variance given
n=25 represent the sample size
Solution
The confidence interval for the true mean is given by :
(1)
The sample deviation would be 
The degrees of freedom are given by:
The Confidence is 0.954 or 95.4%, the value of 
and 
, assuming that we can use the normal distribution in order to find the quantile the critical value would be 
The confidence interval would be
And the best option would be:
c. 1450 +/- 12
Answer:
5040
Step-by-step explanation:
There are 7 possibilities for the first spot, 6 for the second, etc.
7*6*5*4*3*2*1=5040
6(7 - 2)
6(5)
Check:
7*6 = 42
2*6 = 12
42-12 = 30 = 6(5) :)
Answer: move right 4, move up 4
Step-by-step explanation:
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