Answer:
<em>Quantisation</em><em> </em><em>is</em><em> </em><em>total</em><em> </em><em>charge</em><em> </em><em>by</em><em> </em><em>number</em><em> </em><em>of</em><em> </em><em>electrons</em><em>.</em><em> </em>
<em>q</em><em>=</em><em>ne</em>
<em>here</em><em> </em><em>q</em><em> </em><em>is</em><em> </em><em>quantisation</em>
<em>n</em><em> </em><em>is</em><em> </em><em>number</em><em> </em><em>of</em><em> </em><em>electrons</em>
<em>e</em><em> </em><em>is</em><em> </em><em>standard</em><em> </em><em>charge</em><em> </em><em>that</em><em> </em><em>is</em>
<em>e</em><em>=</em><em> </em><em>1.6 × 10</em><em>p</em><em>o</em><em>w</em><em>e</em><em>r</em><em>-</em><em>1</em><em>9</em><em>C</em>
Explanation:
<h2>HOPE IT WILL HELP YOU✌✌✌✌✌</h2>
<span>If it is known that at 60 °C and 745 torr UF₆ is present only as a gas then we can make the assumption that:
</span>(n/V) = P/RT = (745 torr)/(62.36 L-torr/mol•K)(337 K) = 0.0354 mol/L
Therefore the density will be:
<span>
Density = (352.02 g/mol)(0.0354 mol/L)/(1000 cm³/L) = 0.0125 g/cm³
</span>
Answer:
Mass percent of food dyes = 0.0616%
Explanation:
Given data:
Mass of candy = 47.9 g
Calories = 240
Mass of fat = 10 g
Mass of carbohydrate = 34 g
Mass of protein = 2 g
Mass of food dyes = 29.5 mg
Mass percent of food dyes = ?
Solution:
First of all we will convert the mg into g.
Mass of food dyes = 29.5 mg × 1g /1000 mg = 0.0295 g
Mass percent of food dyes = mass of food dyes / total mass× 100
Now we will put the values.
Mass percent of food dyes = 0.0295 g / 47.9 g × 100
Mass percent of food dyes = 0.000616 × 100
Mass percent of food dyes = 0.0616%
Answer:
I thinks is B
Explanation:
they just look harmful
I also researched and it says its harmful and causes sickness and death
