Answer:
The volume of the sample given is 850 ml, the density given is 0.79 gram per cm. Now the weight of the sample will be,
Weight = volume × density = 850 × 0.79
= 671.5 grams
Weight of the suspended solids given is 0.001 gram
The concentration of the sample can be determined by using the formula,
Concentration = wt. of sample/volume
= [671.5 - 0.001) 10³ mg / 0.85 L
= 789998.82 mg/L or 789998.82 ppm
Now the concentration of suspended solids is.
Css = 0.001 × 10³ mg / 0.85 L = 1.1764 mg per L or 1.1764 ppm
Answer:
For 12.8 g there 0.807 × 10³ formula units.
Explanation:
Given data:
Mass of MgCl₂ = 12.8 g
Formula units for given mass = ?
Solution:
First of all we will calculate the number of moles.
Number of moles = mass/molar masss
Number of moles = 12.8 g/ 95.211 g/mol
Number of moles = 0.134 mol
According to the Avogadro number,
one moles = 6.022 × 10³ formula units
For 0.134 mol,
0.134 × 6.022 × 10³ formula units
0.807 × 10³ formula units
For 12.8 g there 0.807 × 10³ formula units.
Answer:
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