<span>The particles are far apart from each other.</span>
Answer:
The equilibrium partial pressure of O2 is 0.545 atm
Explanation:
Step 1: Data given
Partial pressure of SO2 = 0.409 atm
Partial pressure of O2 = 0.601 atm
At equilibrium, the partial pressure of SO2 was 0.297 atm.
Step 2: The balanced equation
2SO2 + O2 ⇆ 2SO3
Step 3: The initial pressure
pSO2 = 0.409 atm
pO2 = 0.601 atm
pSO3 = 0 atm
Step 4: Calculate the pressure at the equilibrium
pSO2 = 0.409 - 2X atm
pO2 = 0.601 - X atm
pSO3 = 2X
pSO2 = 0.409 - 2X atm = 0.297
X = 0.056 atm
pO2 = 0.601 - 0.056 = 0.545 atm
pSO3 = 2*0.056 = 0.112 atm
Step 5: Calculate Kp
Kp = (pSO3)²/((pO2)*(pSO2)²)
Kp = (0.112²) / (0.545 * 0.297²)
Kp = 0.261
The equilibrium partial pressure of O2 is 0.545 atm
Answer:
NH₃ = 17.03 g/mol
Explanation:
Molecular weight is calculated by adding the atomic mases of all the atoms present in a molecule.
Like in case ammonia three hydrogen atoms and one nitrogen atom are present.
1 H = 1.01 g/mol
1 N = 14 g/mol
NH₃ = 14 + (1.01×3)
NH₃ = 17.03 g/mol
12.electrons
13.13
14.aluminum has 14 neutron.
<u>Answer:</u>
Shifts the equilibrium to side that has fewest moles of gas.
<u>Explanation</u>:
"Le Chatelier's principle", also called as the equilibrium law in chemistry explains the effect in different states on some chemical equilibria. It states that when a system is in equilibrium for a long time, it is subject to change in pressure, volume, temperature or condensation.
In this case, with an "increase" in pressure, there would be a shift to the side of fewer moles of gas. Mainly the change towards the reactants.
