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3 years ago

Object height 10cm is placed in front of plane mirror.The height of the image will be_______?

1 answer:

7 0

Object height 10cm is placed in front of plane mirror. The height of the image will also be 10cm as the height of image is same as height of object in the case of plane mirror

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Why was the microscope and its improvement an important part of the development of the cell theory?

netineya [11]

Answer:it’s is part of the cell theory because they where studying cells and to see it you need a microscope

Explanation:basically in the answer area

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3 years ago

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Magnetic field lines are more concentrated at the poles of the magnet<br> True<br> False

yKpoI14uk [10]

Answer:

True! UwU

Explanation:

the magnetic field is strongest near to the poles of the magnet were the lines of flux are more closely spaced.

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3 years ago

URGENTTT PLEASE HELP

mel-nik [20]

This doesn’t make any sense

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3 years ago

A radioactive nuclide of atomic number emits an electron, then the daughter nuclide emits a gamma ray. What is the atomic number

Galina-37 [17]

Answer:

correct answer is b Z --->Z+1

Explanation:

In the processes of radioactive decay there are three basic processes the emission of alpha particles and the emission of beta rays and the emission of ayos range

The emission of a beta ray implies the transformation of a neutral into a proton, which implies the increase of the atomic number in a unit

Z ----> Z +1

the atomic mass does not change since the mass of the two particles is practically the same, to balance the reaction antineutrino must also be emitted

The daughter particle is in an execrated state and passes to its base state with the emission of a gamma ray that does not change its atomic number or its atomic mass.

Consequently, from the above the correct answer is b

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3 years ago

What is the electric potential of a 2.2 µC charge at a distance of 6.3 m from the charge? Recall that Coulomb’s constant is k =

iren2701 [21]

1) The electric potential at a distance r from a single point charge is given by
$V(r) = k \frac{q}{r}$
where k is the Coulomb's constant, q is the charge and r is the distance from the charge.

The charge in this problem is
$q=2.2 \mu C =2.2 \cdot 10^{-6} C$
So the potential at distance $r=6.3 m$ is
$V=k \frac{q}{r}=(8.99 \cdot 10^9 Nm^2 C^{-2}) \frac{2.2 \cdot 10^{-6} C}{6.3 m}=3139 V$

2) By using the same formula as before, we can find the electric potential at distance r=99 m from the charge:
$V=k \frac{q}{r}=(8.99 \cdot 10^9 Nm^2C^{-2}) \frac{2.2 \cdot 10^{-6} C}{99 m}=198 V$

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4 years ago

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Object height 10cm is placed in front of plane mirror.The height of the image will be_______?​

Object height 10cm is placed in front of plane mirror.The height of the image will be_______?