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fenix001 [56]
3 years ago
12

Find the inequality represented by the graph​

Mathematics
2 answers:
UkoKoshka [18]3 years ago
8 0

Answer:

y < 5/2x + 5

Step-by-step explanation:

slope goes up 5, then over 2 ( 5 on top, 2 on bottom --> 5/2)

y intercept is +5

Igoryamba3 years ago
4 0

Answer:

Plug your slope and a point into the formula y = mx + B, in which "m" is the slope, (x, y) is a point on the line and "b" is the y-intercept, to find the equation governing the inequality line. Plugging in (0, 0), you obtain 0 = 0 + b, so b = 0. Rewriting the equation, you obtain y = x/2

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Rectangular prism is 5.9 millimeters wide and 20 millimeters high. Its surface area is 733.28 square millimeters. What is the le
Ray Of Light [21]

Answer:

The the length of the rectangular prism is 6.64 mm

Step-by-step explanation:

knowing the surface area of the rectangular prism is the sum up of all areas of the prisma we have

(20 * 5.9)*2 + (20*X)*2 + (5.9*X)*2 = 733.28  

236 + 40X + 34.81X = 733.28

X = 6.64 mm

7 0
4 years ago
A researcher is 95% confident that the interval from 5.2 hours to 7.8 hours captures u = the true mean amount of time
igor_vitrenko [27]
<h3>Answer: Choice B</h3>

No, this is not a plausible value for the population mean, because 5 is not within the 95% confidence interval.

====================================================

Explanation:

The greek letter mu is the population mean. It has the symbol \mu which looks like the letter 'u' but with a tail at the front or left side.

The question is asking if mu = 5 is plausible if the researcher found the 95% confidence interval to be 5.2 < mu < 7.8

We see that 5 is <u>not</u> in that interval. It's a bit to the left of 5.2

Since mu = 5 is not in the interval, it's not a plausible value for the population mean.

Have we ruled it out with 100% confidence? No. Such a thing is not possible. There's always room for (slight) error. The researcher would need to do a census to be fully confident; however, such practices are very time consuming and expensive. This is the main reason why statistics is important to try to estimate the population with a sample.

8 0
3 years ago
Solve each equation. Check your solution.<br><br><br> 3x 32 = 7x + 28
skad [1K]

Answer:

x= 28 /89

Step-by-step explanation:

3x(32)=7x+28

Step 1: Simplify both sides of the equation.

96x=7x+28

Step 2: Subtract 7 from both sides.

96x   7x+28

−7             −7

89x=28

Step 3: Divide both sides by 89.

89x /89 = 28 /89

6 0
3 years ago
Find the probability of spinning a 2 and 4 and rolling a 6?
Tasya [4]

Answer:

Just by simply adding the two quantities you can get the net change.  $67.12 +(addition sign because we want the net change) $2.56= $69.68.  The last number is the net change!

Step-by-step explanation:

7 0
4 years ago
Read 2 more answers
If the mean weight of 4 backfield members on the football team is 221 lb and the mean weight of the 7 other players is 202 lb, w
MatroZZZ [7]

Let x_1, x_2, x_3, x_4, x_5, x_6, x_7, x_8, x_9, x_{10}, x_{11} be the weight of i-th player.

1. If the mean weight of 4 backfield members on the football team is 221 lb, then

\dfrac{x_1+x_2+x_3+x_4}{4}=221\ lb.

2. If the mean weight of the 7 other players is 202 lb, then

\dfrac{x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}}{7}=202\ lb.

3. From the previous statements you have that

x_1+x_2+x_3+x_4=221\cdot 4=884 \lb,\\ \\x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}=202\cdot 7=1414\ lb.

Add these two equalities and then divide by 11:

x_1+x_2+x_3+x_4+x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}=884+1414=2298\ lb,\\ \\\dfrac{x_1+x_2+x_3+x_4+x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}}{11}=\dfrac{2298}{11}=208\dfrac{10}{11}\ lb.

Answer: the mean weight of the 11-person team is 208\dfrac{10}{11}\ lb.

4 0
3 years ago
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