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nordsb [41]
3 years ago
12

What is the frequency of light with a wave- length of 4.0 ×10−7 m?

Chemistry
1 answer:
Kisachek [45]3 years ago
7 0

7.5x10^14 Hz. I just worked it out on paper.

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Light shining on a strip of metal can dislodge electrons. Do you think this is more consistent with light being made up of waves
Naya [18.7K]

Answer:

The correct answer to the following question will be "Particles".

Explanation:

  • A particle seems to be a little component of something, it's little. When you're talking about a subatomic particle, that would be a structured user likely won't see because it's quite unbelievably thin, but it has a tiny mass as well as structural integrity. Such particles seem to be tinier than that of the particles or atoms.
  • Such that the light which shines on the bit of metal could dissipate electrons, the particles seem to be more compatible with the light.
5 0
3 years ago
Read 2 more answers
In a titration of a solution of unknown concentration of calcium hydroxide against hydrochloric acid (concentration 0.9mol/dm3),
bearhunter [10]
Hi dear
I hope that will be helpful

6 0
2 years ago
in order for Drix to stay in Frank's body, he"ll need a lawyer. where does Ozzie suggest he go to get one? in, "the biology of o
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4 0
3 years ago
Silver (Ag) has two stable isotopes: 107Ag, 106.90 amu, and 109Ag, 108.90 amu. If the average atomic mass of silver is 107.87 am
inysia [295]

Answer:

  • The abundance of 107Ag is 51.5%.
  • The abundance of 109Ag is 48.5%.

Explanation:

The <em>average atomic mass</em> of silver can be expressed as:

107.87 = 106.90 * A1 + 108.90 * A2

Where A1 is the abundance of 107Ag and A2 of 109Ag.

Assuming those two isotopes are the only one stables, we can use the equation:

A1 + A2 = 1.0

So now we have a system of two equations with two unknowns, and what's left is algebra.

First we<u> use the second equation to express A1 in terms of A2</u>:

A1 = 1.0 - A2

We <u>replace A1 in the first equation</u>:

107.87 = 106.90 * A1 + 108.90 * A2

107.87 = 106.90 * (1.0-A2) + 108.90 * A2

107.87 = 106.90 - 106.90*A2 + 108.90*A2

107.87 = 106.90 + 2*A2

2*A2 = 0.97

A2 = 0.485

So the abundance of 109Ag is (0.485*100%) 48.5%.

We <u>use the value of A2 to calculate A1 in the second equation</u>:

A1 + A2 = 1.0

A1 + 0.485 = 1.0

A1 = 0.515

So the abundance of 107Ag is 51.5%.

3 0
3 years ago
Would a pure substance ever settle out and form two distinct layers? Explain your reasoning.
garik1379 [7]

Answer:

No, the only way they can be separated is through chemical methods. ... A compound is made up of two or more elements that are chemically combined and elements are combined to form a compound.

Explanation:

6 0
3 years ago
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