Answer:
a) ![1.94 \frac{rad}{s}](https://tex.z-dn.net/?f=1.94%20%5Cfrac%7Brad%7D%7Bs%7D)
b) ![9.12\frac{m}{s}](https://tex.z-dn.net/?f=9.12%5Cfrac%7Bm%7D%7Bs%7D)
c) Towards the center of the centrifuge
Explanation:
a)
Becuse the centrifuge rotates in circular motion, there's an angular acceleration tha simulates high gravity accelerations
![a_{rad}=\omega r^{2}](https://tex.z-dn.net/?f=a_%7Brad%7D%3D%5Comega%20r%5E%7B2%7D%20)
with r the radius and ω the amgular velocity, in or case
so:
and g=9.8![\frac{m}{s^{2}}](https://tex.z-dn.net/?f=%20%5Cfrac%7Bm%7D%7Bs%5E%7B2%7D%7D)
solving for ω:
![\omega=\frac{3.5g}{r^2}=\frac{3.5*9.8}{4.2^2}](https://tex.z-dn.net/?f=%20%5Comega%3D%5Cfrac%7B3.5g%7D%7Br%5E2%7D%3D%5Cfrac%7B3.5%2A9.8%7D%7B4.2%5E2%7D)
![\omega = 1.94 \frac{rad}{s}](https://tex.z-dn.net/?f=%20%5Comega%20%3D%201.94%20%5Cfrac%7Brad%7D%7Bs%7D)
b) Linear speed (v) and angular speed are related by:
![v=\omega r =(1.94)(4.7)](https://tex.z-dn.net/?f=v%3D%5Comega%20r%20%3D%281.94%29%284.7%29%20)
![v= 9.12\frac{m}{s}](https://tex.z-dn.net/?f=%20v%3D%209.12%5Cfrac%7Bm%7D%7Bs%7D)
c) The apparent weigth is pointing towards the center of the circle, becuse angular acceleration is pointing in that direction.
Lindsay has to fly this plane towards this direction [W 12.5° S] to get to Hamilton.
From this question, the plane is still up in the air.
We have wind blowing in [W 60° N ]
To solve the problem we have to make use of the sine rule
![\frac{SinA}{a}=\frac{SinB}{b} =\frac{SinC}{c}](https://tex.z-dn.net/?f=%5Cfrac%7BSinA%7D%7Ba%7D%3D%5Cfrac%7BSinB%7D%7Bb%7D%20%3D%5Cfrac%7BSinC%7D%7Bc%7D)
We put the values in the equation, we have:
50/Sinθ = 200/sin60°
The next step is to cross multiply
50 x sin60° = 200Sinθ
50 x 0.8660 = 200sinθ
We make Sin θ the subject
Sine θ = 43.30/200
sine θ = 0.2165
we find the value of θ
θ = sine⁻¹(0.2165)
θ = 12.50
So Lindsay has to fly this plane towards this direction
[W 12.5° S]
Here is a similar question brainly.com/question/13338067?referrer=searchResults
An electron has a negative charge. Hope this helps.
Answer:(a) 4775.2Hz (b) 4.06m/s (c) 19382.15m/s²
Explanation: Given that the frequency of oscilation f, is 760Hz and the maximum displacement x, is 0.85mm= 0.00085m
(a) Angular frequency w= 2πf
w= 2π × 760 = 4775.2Hz
(b) Maximum speed v is given as the product of angular frequency and maximum displacement
V=wx
V= 4775.2 × 0.00085
V= 4.06m/s
(c) The maximum acceleration a
= w²x
= (4775.2)² × (0.00085)
a= 19382.15m/s².
Answer:
When air resistance equals the weight of an object, the object has reached free fall.
Explanation:
- When an object has only force acting on it as gravity then, it experiences free fall.
- During free fall all the forces except gravity is balanced by one another.
- In the question, object's weight is balanced by air resistance so it is in the state of free fall.
- At the null point of free fall, object experiences weightlessness i.e. it feels like object is not attracted by any force.