Answer:
The resulting speed of the ball is;
10 m/s
Explanation:
The given parameters are;
The amount of work done by the lever = 5.0 J
The mass of the ball on which the work is done, m = 0.10 kg
By the principle of conservation of energy, we have;
The work done by the lever = The kinetic energy. K.E., gained by the ball
The kinetic energy, K.E., is given by K.E. = 1/2·m·v²
Where, for the ball, we have;
m = The mass of the ball
v = The resulting speed of the ball
Therefore, by substituting the known values, we have;
The work done by the lever = 5.0 J = The kinetic energy. K.E., gained by the ball = 1/2 × m × v² = 1/2 × 0.10 kg × v²
∴ 5.0 J = 1/2 × 0.10 kg × v²
v² = 5.0 J/(1/2 × 0.10 kg) = 100 m²/s²
v = √(100 m²/s²) = 10 m/s
The resulting speed of the ball, v = 10 m/s.
