We are given the mass of an <span>aluminum sculpture which is 145 kg and a horizontal force equal to 668 Newtons. The coefficient of friction can be determined by dividing the horizontal force by the weight of the object. In this case, 668 N / 145 * 9.8 equal to coeff of friction of 0.47</span>
Answer:

Explanation:
The power dissipated in a resistor is given by the equation:

where
P is the power
I is the current
R is the resistance
We can also rewrite the equation by using Ohm's law:

where V is the potential difference across the resistor. Rewriting R as

The equation for the power becomes

Answer:2√(2)km Southeast
Explanation:
Displacement=√(2)+√(2)=2√(2)km Southeast
Answer:
12.0x84.0=1,008
Explanation:
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The magnitude of the resulting acceleration of the block is 6.14 m/s².
The given parameters;
- <em>mass of the block, m = 2.2 kg</em>
- <em>horizontal force on the block, F = 27 N</em>
- <em>force below the horizontal, 81 N at 60⁰</em>
The net horizontal force on the block is calculated as follows;

The acceleration of the block is calculated as follows;

Thus, the magnitude of the resulting acceleration of the block is 6.14 m/s².
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