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vichka [17]
3 years ago
10

It is winter where Jenna lives. It's been snowing all day, but now the snow has changed to sleet and then freezing rain. What is

happening to cause these changes? In your answer, explain how snow, sleet, and freezing rain form.
I don’t need the answer just some help. Also is what is causing this the temperature, and if so is it decreasing or increasing?

Thanks...
Physics
1 answer:
dem82 [27]3 years ago
3 0
All I can say is it is decreasing
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Irregular galaxies are very large. True or False?
xenn [34]
It's false i hope this helps :)

5 0
2 years ago
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During photosynthesis, what is the source of the carbon in<br> the sugar (CH20) that is created?
irakobra [83]

Answer:

Carbon dioxide

Explanation:

During photosynthesis cells use carbon dioxide and energy of sun to make sugar molecules and oxygen.

Hope i helped u...

8 0
2 years ago
Will give brainlist.
Lera25 [3.4K]

Answer:

<u>Displacement (km)</u>

Explanation:

The y axis is the vertical axis pointing up and down. This is labeled as the the displacement (km) in the graph.

6 0
2 years ago
A carbon rod with a radius of 1.9 mm is used to make a resistor. What length of the carbon rod should be used to make a 3.7 Ω re
vladimir2022 [97]

Answer:

Length = 2.32 m

Explanation:

Let the length required be 'L'.

Given:

Resistance of the resistor (R) = 3.7 Ω

Radius of the rod (r) = 1.9 mm = 0.0019 m [1 mm = 0.001 m]

Resistivity of the material of rod (ρ) = 1.8\times 10^{-5}\ \Omega\cdot m

First, let us find the area of the circular rod.

Area is given as:

A=\pi r^2=3.14\times (0.0019)^2=1.13\times 10^{-5}\ m^2

Now, the resistance of the material is given by the formula:

R=\rho( \frac{L}{A})

Express this in terms of 'L'. This gives,

\rho\times L=R\times A\\\\L=\frac{R\times A}{\rho}

Now, plug in the given values and solve for length 'L'. This gives,

L=\frac{3.7\ \Omega\times 1.13\times 10^{-5}\ m^2}{1.8\times 10^{-5}\ \Omega\cdot m}\\\\L=\frac{4.181}{1.8}=2.32\ m

Therefore, the length of the material required to make a resistor of 3.7 Ω is 2.32 m.

5 0
3 years ago
A particle moves along the curve below. y = sqrt(1 + x^3) As it reaches the point (2, 3), the y-coordinate is increasing at a ra
blagie [28]

Answer:7 cm/s

Explanation:

Given

Particle move along curve

y=\sqrt{1+x^3}

As it reaches the (2,3) its y coordinate is increasing at 14 cm/s

Differentiating y w.r.t time

\frac{\mathrm{d} y}{\mathrm{d} t}=\frac{3x^2}{2\sqrt{1+x^3}}\times \frac{\mathrm{d} x}{\mathrm{d} t}

Now at (2,3)

\frac{\mathrm{d} y}{\mathrm{d} t}=\frac{3\cdot 2^2}{2\sqrt{1+2^3}}\times \frac{\mathrm{d} x}{\mathrm{d} t}

14=\frac{3\times 4}{2\times \sqrt{9}}\times \frac{\mathrm{d} x}{\mathrm{d} t}

\frac{\mathrm{d} x}{\mathrm{d} t}=7 cm/s

7 0
2 years ago
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