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vichka [17]
3 years ago
10

It is winter where Jenna lives. It's been snowing all day, but now the snow has changed to sleet and then freezing rain. What is

happening to cause these changes? In your answer, explain how snow, sleet, and freezing rain form.
I don’t need the answer just some help. Also is what is causing this the temperature, and if so is it decreasing or increasing?

Thanks...
Physics
1 answer:
dem82 [27]3 years ago
3 0
All I can say is it is decreasing
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A 5000-lb wrecking ball hangs from a 50-ft cable of density 10 lb/ft attached to a crane. Calculate the work done if the crane l
aniked [119]

Answer:

total work is = 52450 J

Explanation:

given data

mass =  5000-lb

density = 10 lb/ft

height = 50 ft

solution

as we will treat here cable and ball are separate  

and

here work need to lift cable is

w = (10Δy )(9.8 y )  j

and

now summing all segment of cable

so passing limit Δy to 0

so total work need

= \int\limits^{10}_0 {98y} \, dy    

= [49 y^2]^{50}_0

= 2450J

so lifting 5000 lb wrcking 50 m  required additional 5000 + 2450

so total work is = 52450 J

3 0
3 years ago
On planet X, the absolute pressure at a depth of 2.00 m below the surface of a liquid nitrogen lake is 5.00 × 105 N/m2 . At a de
eimsori [14]

Answer:

300000.01008 Pa

123.76237 m/s²

Explanation:

\rho = Density of liquid nitrogen = 808 kg/m³

h = Depth

g = Acceleration due to gravity

P = Atmospheric pressure

Absolute Pressure is given by

Below 2 m from surface

P_a=P+\rho gh\\\Rightarrow 5\times 10^5=P+808g\times 2

Below 5 m from surface

P_a=P+\rho gh\\\Rightarrow 8\times 10^5=P+808g\times 5

Subtracting the above equations we get

-3\times 10^5=-808g3\\\Rightarrow g=\frac{3\times 10^5}{808\times 3}\\\Rightarrow g=123.76237\ m/s^2

The acceleration due to gravity on the planet is 123.76237 m/s²

Equating the value of g in the first equation

5\times 10^5=P+808\times 123.76237\times 2\\\Rightarrow P=5\times 10^5-808\times 123.76237\times 2\\\Rightarrow P=300000.01008\ Pa

The atmospheric pressure on the planet is 300000.01008 Pa

7 0
4 years ago
The average human has a density of 945 kg/m3 after inhaling and 1020 kg/m3 after exhaling. (a) Without making any swimming movem
Gala2k [10]

Answer:

20% of the human body float above the surface in the dead sea.

Explanation:

Given data,

The human density after inhaling, d₁ = 945 kg/m³

The human density after exhaling, d₂ = 1020 kg/m³

Therefore the average human density, d = 982.5 kg/m³

The density of the dead sea, D = 1230 kg/m³

The percentage of density of human body to the dead sea is,

                                   P % = (982.5 / 1230) x 100 %

                                           = 80 %

Therefore, the human body has 80% of dead sea density.

Hence, 20% of the human body float above the surface in the dead sea.

8 0
4 years ago
What is the quantity of matter that an object contains called? A. mass B. weight C. volume D. density
Setler79 [48]
The answer would be A) Mass
3 0
3 years ago
a moving freight car collides with an identical one that is at rest what happen to the second car after the collison
irakobra [83]
It moves backwards do to the impact. this is because force can not be created nor destroyed so it is transferred.<span />
7 0
3 years ago
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