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Jlenok [28]
4 years ago
6

calculate the force exerted on a rocket given that the propelling gases are expelled at a rate of 1500 kg/s with a speed of 4.0x

10^4 (at the moment of take off)
Physics
1 answer:
Tanya [424]4 years ago
3 0

we know that momentum is given as

P = mv

where P = momentum , m = mass , v = velocity

taking derivative both side relative to "t"

dP/dt = v (dm/dt)

we know that :  dP/dt  = F = force

hence

F = v (dm/dt)

given that :

dm/dt = rate of mass expelled = 1500 kg/s

v = velocity = 4 x 10⁴ m/s

hence  , inserting the values in the above formula

F = (4 x 10⁴) (1500)

F = 6 x 10⁷ N



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