Answer:
E = k Q₁ / r²
Explanation:
For this exercise that asks us for the electric field between the sphere and the spherical shell, we can use Gauss's law
Ф = ∫ E .dA = 
/ ε₀
where Ф the electric flow, qint is the charge inside the surface
To solve these problems we must create a Gaussian surface that takes advantage of the symmetry of the problem, in this almost our surface is a sphere of radius r, that this is the sphere of and the shell, bone
R <r <R_a
for this surface the electric field lines are radial and the radius of the sphere are also, therefore the two are parallel, which reduces the scalar product to the algebraic product.
E A = q_{int} /ε₀
The charge inside the surface is Q₁, since the other charge Q₂ is outside the Gaussian surface, therefore it does not contribute to the electric field
q_{int} = Q₁
The surface area is
A = 4π r²
we substitute
E 4π r² = Q₁ /ε₀
E = 1 / 4πε₀ Q₁ / r²
k = 1/4πε₀
E = k Q₁ / r²
To solve this problem we will apply the concepts related to resistance as a function of temperature, product of the relationship between the squared voltage and the power. Mathematically this is,
Here,
R = Resistance (At function of temperature)
v = Voltage
P = Power
Then we have,
R at 140°C (7 times room temperature),
The relationship between normal temperature and increased temperature would then be given by,
Therefore the correct value of the group of answer is 1350
Answer:
the major difference between the rate of diffusion between urea and albumin is that urea diffused more slowly because it is larger than albumin.
Explanation:
As described in activity 1, the major difference between the rate of diffusion between urea and albumin is that urea diffused more slowly because it is larger than albumin. Urea basically is an heavy compound, thus it is at the base of the chain reactions which which major purpose is to break down the amino acids that make up proteins. Albumin on the other hand is a form of protein that simply helps in the transmission of blood and prevent blood from flowing through to other tissue in the body. The liver produces the albumin the body. So going back to the question, the major difference between the rate of diffusion between urea and albumin is that urea diffused more slowly because it is larger than albumin.
Answer: The value of x is -6.
Explanation:
To calculate the value of 'x', we need to solve each function happening inthe equation.
The equation provided to us is 
To solve this, we will multiply 4x with 2 and then subtract the like terms and finally, we evaluate the value of 'x'.
Hence, the value of x will be -6.
its 13.98. it's simple multiplication 3* 4.66= 13.98
