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iragen [17]
4 years ago
11

Can someone please explain how to do these please​

Physics
1 answer:
Basile [38]4 years ago
4 0

Answer:

2.  10.1376

Explanation:

10 to the -3 power is 0.01

1.32 times 0.01 is 0.0132

teaspoons in a gallon - 768

0.0132 times 768 is 10.1376

Got the first one; can you try the rest?

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2. A 2kg body attached to a spring undergoes a SHM of amplitude 0.4m and period
Rudik [331]

Answer:

a) 12.8 N

b) 3.2 m/s²

Explanation:

I'm guessing the period is 0.5π s.

Period of a spring in simple harmonic motion is:

T = 2π √(m/k)

Given T = 0.5π and m = 2 kg:

0.5π = 2π √(2/k)

0.25 = √(2/k)

0.0625 = 2/k

k = 32

The spring constant is 32 N/m, and the maximum displacement is 0.4 m.  The maximum force can be found with Hooke's law:

F = kx

F = (32 N/m) (0.4 m)

F = 12.8 N

The acceleration can be found with Newton's second law:

∑F = ma

kx = ma

(32 N/m) (0.2 m) = (2 kg) a

a = 3.2 m/s²

8 0
4 years ago
Alkaline batteries have the advantage of putting out constant voltage until very nearly the end of their life. How long will an
Sidana [21]

Answer:

Explanation:

Voltage, V = 1.58 V

Power, P = 1 W

1 A.h

Charge, Q = 1 A.h = 1 x 3600 A.s = 3600 C

Power x time = Voltage x charge

1 x t = 1.58 x 3600

t = 1.58 x 3600 second

t = 1.58 hours

8 0
4 years ago
The concrete slab of a basement is 11 m long, 8 m wide, and 0.20 m thick. During the winter, temperatures are nominally 17°C and
mina [271]

Answer:

\frac{dQ}{dt}= 4312 W

Explanation:

As we know that base of the slab is given as

A = 11 \times 8

A = 88 m^2

now we know that rate of heat transfer is given as

\frac{dQ}{dt} = \frac{kA}{x} (T_2 - T_1)

here we know that

k = 1.4 W/m k

Also we have

x =0.20

\frac{dQ}{dt} = \frac{1.4(88)}{0.20}(17 - 10)

\frac{dQ}{dt}= 4312 W

7 0
3 years ago
What do you think would happen to the boiling point of water if you were to cook pasta near the Dead Sea in Israel, which is 1,2
mina [271]

Answer:

I think it will be the same.

5 0
3 years ago
Read 2 more answers
The acceleration due to gravity on earth is 9.8m/s2. What is the weight of a 75 kg person on earth?
MissTica
Weight= 9.8*75=735N
OptionD
7 0
3 years ago
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