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3 years ago

Which statement is true for objects in dynamic equilibrium?

Physics

2 answers:

allsm [11]3 years ago

7 0

Answer:d

Explanation:

I think I've done this

balu736 [363]3 years ago

6 0

Answer:

A objects have zero acceleration

Explanation:

I did this on Plato and it was right

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A,b, e are complete. Help on the others would be so appreciated!!

bixtya [17]

Answer:

serie Ceq=0.678 10⁻⁶ F and the charge Q = 9.49 10⁻⁶ C

Explanation:

Let's calculate all capacity values

a) The equivalent capacitance of series capacitors

1 / Ceq = 1 / C1 + 1 / C2 + 1 / C3 + 1 / C4 + 1 / C5

1 / Ceq = 1 / 1.5 + 1 / 3.3 + 1 / 5.5 + 1 / 6.2 + 1 / 6.2

1 / Ceq = 1 / 1.5 + 1 / 3.3 + 1 / 5.5 + 2 / 6.2

1 / Ceq = 0.666 + 0.3030 +0.1818 +0.3225

1 / Ceq = 1,147

Ceq = 0.678 10⁻⁶ F

b) Let's calculate the total system load

Dv = Q / Ceq

Q = DV Ceq

Q = 14 0.678 10⁻⁶

Q = 9.49 10⁻⁶ C

In a series system the load is constant in all capacitors, therefore, the load in capacitor 5.5 is Q = 9.49 10⁻⁶ C

c) The potential difference

ΔV = Q / C5

ΔV = 9.49 10⁻⁶ / 5.5 10⁻⁶

ΔV = 1,725 V

d) The energy stores is

U = ½ C V²

U = ½ 0.678 10-6 14²

U = 66.4 10⁻⁶ J

e) Parallel system

Ceq = C1 + C2 + C3 + C4 + C5

Ceq = (1.5 +3.3 +5.5 +6.2 +6.2) 10⁻⁶

Ceq = 22.7 10⁻⁶ F

f) In the parallel system the voltage is maintained

Q5 = C5 V

Q5 = 5.5 10⁻⁶ 14

Q5 = 77 10⁻⁶ C

g) The voltage is constant V5 = 14 V

h) Energy stores

U = ½ C V²

U = ½ 22.7 10-6 14²

U = 2.2 10⁻³ J

8 0

3 years ago

You have a battery marked " 6.00 V 6.00 V ." When you draw a current of 0.383 A 0.383 A from it, the potential difference betwee

Archy [21]

Answer:

V = 4.81 V

Explanation:

As the potential difference between the battery terminals, is less than the rated value of the battery, this means that there is some loss in the internal resistance of the battery.
We can calculate this loss, applying Ohm's law to the internal resistance, as follows:

$V_{rint} = I* r_{int}$

The value of the potential difference between the terminals of the battery, is just the voltage of the battery, minus the loss in the internal resistance, as follows:

$V = V_{b} - V_{rint} = 5.03 V = 6.0 V - 0.383 A* r_{int}$

We can solve for rint, as follows:

$r_{int} = \frac{V_{b}-V}{I} =\frac{6.0V-5.03V}{0.383A} = 2.53 \Omega$

When the circuit draws from battery a current I of 0.469A, we can find the potential difference between the terminals of the battery, as follows:

$V = V_{b} - V_{rint} = 6.0 V - 0.469 A* 2.53 \Omega= 6.0 V - 1.19 V = 4.81 V$

As the current draw is larger, the loss in the internal resistance will be larger too, so the potential difference between the terminals of the battery will be lower.

5 0

3 years ago

PLEASE ANSWER ASAP!.!.!!.!!!!.!.!.

lbvjy [14]

1. Most PE, because PE is directly proportional to distance (height)
Height: 100 meters
Speed: 0 mph

2. Most KE, because KE is directly proportional to speed
Height: 10 meters
Speed: 40 mph

3. Most TE, average KE
Height: 10 meters
Speed: 40 mph

4. The skater gains thermal energy as she goes down the slope, because the speed of the skater increases, so it increases the total kinetic energy of the particles, and makes them vibrate faster, resulting in a higher temperature.

8 0

3 years ago

A man, holding a weight in each hand, stands at the center of a horizontal frictionless rotating turntable. The effect of the we

Alex_Xolod [135]

Answer:

w = 2w₀ the angular velocity of man doubles

Explanation:

In this exercise, releasing the weights reduces the moment of inertia

I= I₀ / 2

Therefore, since the platform system plus man is isolated, the kinetic moment must be conserved

L₀ = L

I₀ w₀ = I w

I₀ w₀ = I₀ / 2 w

w = 2w₀

therefore the angular velocity of man doubles

7 0

3 years ago

C4. A 50.0 kg boy runs at 10.0 m/s, jumps on a cart and rolls off at 2.50 m/s. What is the mass of the cart

Hunter-Best [27]

Answer:

The mass of the cart is 150 kg.

Explanation:

Given that,

Mass of a boy, m₁ = 50 kg

Initial speed of boy, u₁ = 10 m/s

Initial speed of car, u₂ = 0 (at rest)

The speed of the cart with the boy on it is 2.50 m/s, V = 2.5 m/s

Let m₂ is the mass of the cart. Using the conservation of momentum as follows :

$m_1u_1+m_2u_2=(m_1+m_2)V\\\\50(10)+m_2(0)=(50+m_2)(2.5)\\\\500=125+2.5m_2\\\\375=2.5m_2\\\\m_2=150\ kg$

So, the mass of the cart is 150 kg.

3 0

2 years ago