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krek1111 [17]
3 years ago
14

Which statement is true for objects in dynamic equilibrium?

Physics
2 answers:
allsm [11]3 years ago
7 0

Answer:d

Explanation:

I think I've done this

balu736 [363]3 years ago
6 0

Answer:

A objects have zero acceleration

Explanation:

I did this on Plato and it was right

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Read no.4<br><br> which newtons law is this?<br><br> 1,2 and 3 only
horsena [70]

Explanation:

In the first law, an object will not change its motion unless a force acts on it. In the second law, the force on an object is equal to its mass times its acceleration. In the third law, when two objects interact, they apply forces to each other of equal magnitude and opposite direction.

8 0
2 years ago
Three importance of SI system​
diamong [38]

Answer:

Firstly they are, by design, easy to use in most scientific and engineering calculations; you only ever have to consider multiples of 10. If I’m given a measurement of 3.4 kilometres, I can instantly see that it’s 3′400 metres, or 0.0034 Megametres, or 3′400′000 millimetres. It’s not even necessary to use arithmetic, I just have to remember the definitions of the prefixes (“kilo” is a thousand, “megametre” is a million, “milli” is a thousandth) and shift the decimal point across to the left or the right. This is especially useful when we’re considering areas, speeds, energies, or other things that have multiple units; for instance,

1 metre^2 = (1000millimetre)^2 = 1000000 mm^2.

If we were to do an equivalent conversion in Imperial, we would have

1 mile^2 = (1760 yards)^2

and we immediately have to figure out what the square of 1760 is! However, the fact that SI is based on multiples of 10 has the downside that we can’t consider division by 3, 4, 8, or 12 very easily.

Secondly they are (mostly) defined in terms of things that are (or, that we believe to be) fundamental constants. The second is defined by a certain kind of radiation that comes from a caesium atom. The metre is defined in terms of the second and the speed of light. The kelvin is defined in terms of the triple point of water. The mole is the number of atoms in 12 grams of carbon-12. The candela is defined in terms of the light intensity you get from a very specific light source. The ampere is defined using the Lorentz force between two wires. The only exception is the kilogram, which is still defined by the mass of a very specific lump of metal in a vault in France (we’re still working on a good definition for that one).

Thirdly, most of the Imperial and US customary units are defined in terms of SI. Even if you’re not personally using SI, you are probably using equipment that was designed using SI.

8 0
4 years ago
This type of reaction is most like breaking a rack of balls at the start of a game of pool:
Svet_ta [14]
The answer is b fission hope this helps

5 0
4 years ago
Why do objects appear to be bent when partially submerged under water?
kozerog [31]
<span>when an object is submerged in the water it losses its weight as accordinglyto</span>
8 0
3 years ago
For atomic hydrogen, the Paschen series of lines occurs when nf = 3, whereas the Brackett series occurs when nf = 4 in the equat
zvonat [6]

Answer:

(\lambda_{max} )_{brackett} < (\lambda_{min} )_{paschen}

So the two wavelength range will over lap

Explanation:

The Rydberg equation is given by

\frac{1}{\lambda} =\frac{2\pi mk^2e^4}{h^3c} t (\frac{1}{n^2_f}-\frac{1}{n^2_i}  )

m is the mass of electron

k = 1/4π∈₀

∈₀ = is the permitivity of free space

e is the charge of electron

h is the plank constant

c is the speed of light in vaccum

z is the atomic number = 1

\frac{1}{\lambda} =R (\frac{1}{n^2_f}-\frac{1}{n^2_i}  )

where R is the  Rydberg constant = 1.097373 × 10⁷m⁻¹

For  Paschen series of H spectrum

n_f = 3

n_i = 5,6,7 ...

in Paschen series of H spectrum

The maximum wavelength occur for n_i = 4

\frac{1}{\lambda_m_a_x } =(1.097373 \times 10^7)(\frac{1}{9} - \frac{1}{16} )\\\\\lambda_m_a_x=1874.6nm

The minimum wavelength occur for n_i = ∞

\frac{1}{\lambda_m_i_n } =(1.097373 \times 10^7)(\frac{1}{9} - \frac{1}{_o_o} )\\\\\lambda_m_a_x=820.14nm

The brackett series of H spectrum

The maximum wavelength occur for n_i = 4

\frac{1}{\lambda_m_a_x } =(1.097373 \times 10^7)(\frac{1}{16} - \frac{1}{25} )\\\\\lambda_m_a_x=4050.05nm

The minimum wavelength occur for n_i = ∞

\frac{1}{\lambda_m_i_n } =(1.097373 \times 10^7)(\frac{1}{16} - \frac{1}{_o_o} )\\\\\lambda_m_a_x=1458.03nm

(\lambda_{max} )_{brackett} < (\lambda_{min} )_{paschen}

So the two wavelength range will over lap

8 0
3 years ago
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