Answer:
B: leaving metal outside in the rain until rust forms an it's surface
Let the first car's average speed be x
The second car's speed would be x+5




So the speed of the slower car is 50mph, and the speed of the faster car is 55mph
Answer:
always same
Explanation:
velocity and speed are same upto some extend but velocity is vector while speed is scalar quantity
To solve this problem we must rely on the equations of the simple harmonic movement that define the period as a function of length and gravity as

Where
l = Length
g = Gravity
Re-arrange to find L,

Our values are given as


Replacing,



Therefore the height would be 25.348m
The initial velocity of a car that accelerates at a constant rate of 3m/s² for 5 seconds is 12m/s.
CALCULATE INITIAL VELOCITY:
The initial velocity of the car can be calculated by using one of the equation of motion as follows:
V = u + at
Where;
- V = final velocity (m/s)
- u = initial velocity (m/s)
- a = acceleration due to gravity (m/s²)
- t = time (s)
According to this question, a car accelerates at a constant rate of 3 m/s² for 5 seconds. If it reaches a velocity of 27 m/s, its initial velocity is calculated as follows:
u = v - at
u = 27 - 3(5)
u = 27 - 15
u = 12m/s.
Therefore, the initial velocity of a car that accelerates at a constant rate of 3m/s² for 5 seconds is 12m/s.
Learn more about motion at: brainly.com/question/974124