The air pressure in the pressurized tank will be 24014.88 N/m²,196.2 N/m²,2084.625 N/m².
<h3 /><h3>What is pressure?</h3>
The force applied perpendicular to the surface of an item per unit area across which that force is spread is known as pressure.
It is denoted by P. The pressure relative to the ambient pressure is known as gauge pressure.
Pressure is found as the product of the density,acceleraton due to gravity and the height.
P₁=ρ₁gh₁
P₁=13,600 kg/m³×9.81 (m/s²)×0.18 m
P₁=24014.88 N/m²
P₂=ρ₂gh₂
P₂= 1000 kg/m³×9.81 (m/s²)×00.2 m
P₂=196.2 N/m²
P₃=ρ₃gh₃
P₃=850 kg/m³×9.81 (m/s²)×0.25
P₃=2084.625 N/m²
Hence,the air pressure in the pressurized tank will be 24014.88 N/m²,196.2 N/m²,2084.625 N/m².
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Answer:
It can be said to be reliable although it is not valid
Explanation:
This is because Reliability means an indicator of consistency, A measure should produce similar or the same results consistently if it measures the same quantity. So does the thermometer measures over 5days but it is not valid because it deviates from the real value
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Answer:
The force to be applied on the primary piston is 140.63 N.
Explanation:
To solve this problem we apply the following formulas:
Pascal principle: F=P*A Formula (1)
F=Force applied to the piston
P: Pressure
A= Piston area
Formula (2)
d= piston diameter
Nomenclature:
Fp= Force on the primary piston
Fs= Force on the secondary piston
Ap= Primary piston area
As= Secondary piston area
W= car weight
Calculation of the force Fp necessary to support the weight of the car.
Pascal principle: Fp=P*Ap (Equation1)
In (Equation1) we know Ap and we don't know P.
Pressure calculation:
We apply Newton's first law for a balanced Secondary piston -automobile system
Newton's first law: ∑F=0
W-Fs=0
W=Fs
W=P*As
We replace in equation 1:
Calculation of Fp in Newtons (N):
Fp=140.63N
