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Tresset [83]
2 years ago
11

Help, please I will mark the brainliest answer if right!

Chemistry
1 answer:
gavmur [86]2 years ago
6 0

here's your answer dear friend❤❤

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The volume occupied by a gas at STP is 250 L. At what pressure (in atm) will the gas occupy 1500 L, if the temperature is consta
Dennis_Churaev [7]

Answer:

6 atm

Explanation:

Using the formula P1V1=P2V2

P1= Initial Pressure

V1= Initial Volume

P2= Final Pressure

V2= Final Volume

And knowing that at stp gas will always be at 1 atm

250L(P2) = 1500

P2= 6 atm

8 0
2 years ago
Could the cuttlefish tell the difference between the blue and yellow in the lab?​
jeka94

Answer:

<em>yes</em>

Explanation:

the cuttle fish tell the difference between blue and yellow

5 0
1 year ago
The volume of a gas with a pressure of 1.2 atm increases from 1.0 l to 4.0 l. what is the final pressure of the gas, assuming no
Oksana_A [137]
Boyle's law gives the relationship between pressure and volume of gas.
for a fixed amount of gas, at constant temperature the pressure of gas is inversely proportional to its volume.
PV = k
where P - pressure, V - volume and k - constant
P1V1 = P2V2
where parameters for the first instance are on the left side and parameters for the second instance are on the right side.
substituting the values in the equation
1.2 atm x 1.0 L = P x 4.0 L 
P = 0.3 atm
new pressure is 0.3 atm
3 0
3 years ago
Deserts are only found near the equator.
Goshia [24]
True because it is warmer closer to the equator
8 0
3 years ago
2. When heated above 500 ºC, potassium nitrate decomposes according to the equation below. 4KNO3 2K2O + 2N2 + 5O2A.If oxygen is
AysviL [449]

Answer:

(a) The rate of formation of K2O is 0.12 M/s.

The rate of formation of N2 is also 0.12 M/s

(b) The rate of decomposition of KNO3 is 0.24 M/s

Explanation:

(a) From the equation of reaction, the mole ratio of K2O to O2 is 2:5.

Rate of formation of O2 is 0.3 M/s

Therefore, rate of formation of K2O = (2×0.3/5) = 0.12 M/s

Also from the equation of reaction, mole ratio of N2 to O2 is 2:5.

Rate of formation of N2 = (2×0.3/5) = 0.12 M/s

(b) From the equation of reaction, mole ratio of KNO3 to O2 is 4:5.

Therefore, rate of decomposition of KNO3 = (4×0.3/5) = 0.24 M/s

3 0
3 years ago
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