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2 years ago

What is the result when the number 79 is decreased by 17%?

Mathematics

2 answers:

trapecia [35]2 years ago

8 0

Answer:

65.57 should be the correct answer!

Step-by-step explanation:

Here is the whole work I did, hope this helps!

100 - 17 = 83

79 x 0.83 = 65.57

USPshnik [31]2 years ago

6 0

Answer:

65.57

Step-by-step explanation:

Method 1:

$\frac{y}{79} :\frac{17}{100}$

y · 100 = 17 · 79

100y = 1343

100y ÷ 100 = 1343 ÷ 100

y = 13.43

79 - 13.43

65.57

Method 2:

100% - 17% = 83%

$\frac{y}{79} :\frac{83}{100}$

y · 100 = 83 · 79

100y = 6557

100y ÷ 100 = 6557 ÷ 100

y = 65.57

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A bank sampled its customers to determine the proportion of customers who use their debit card at least once each month. A sampl

Zinaida [17]

Answer:

(0.084,0.396)

Step-by-step explanation:

The 99% confidence interval for the proportion of customers who use debit card monthly can be constructed as

$p-z_{\frac{\alpha }{2}} \sqrt{\frac{pq}{n} }$

$p=\frac{x}{n}$

$p=\frac{12}{50}$

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$p-z_{\frac{\alpha }{2}} \sqrt{\frac{pq}{n} }$

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$0.084$

The 99% confidence interval for the proportion of customers who use debit card monthly is (0.084,0.396).

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3 years ago

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Mrac [35]

Answer:

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Step-by-step explanation:

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2 years ago

Read 2 more answers

In tossing four fair dice, what is the probability of tossing, at most, one 3

11Alexandr11 [23.1K]

Answer-

In tossing four fair dice, the probability of getting at most one 3 is 0.86.

Solution-

The probability of getting at most one 3 is, either getting zero 3 or only one 3.

$P(A) =The \ probability \ of \ getting \ zero \ 3 =(\frac{5}{6})(\frac{5}{6})(\frac{5}{6})(\frac{5}{6})=\frac{625}{1296} =0.48$ ( ∵ xxxx )

$P(B) = The \ probability \ of \ getting \ only \ one \ 3 =(4)(\frac{1}{6})(\frac{5}{6})(\frac{5}{6})(\frac{5}{6}) = 0.38$ ( ∵ 3xxx, x3xx, xx3x, xxx3 )

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