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timurjin [86]
3 years ago
8

Solve 1/6 * 6 and 1/6 * 5

Mathematics
1 answer:
Juli2301 [7.4K]3 years ago
7 0
The first answer is 1 and the second is 0.83333.
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Add the following fractions. 3/8 + 5/12 = <br> a 8/20 <br> b 19/24 <br> c 8/24 <br> d 1/3
loris [4]
3/8 + 5/12 = 

B. 19/24
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4 years ago
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In a certain year, the population of Smallburg was $4{,}000.$ In the following year, the population increased by $15\%.$ What wa
makkiz [27]

Answer:

4,600

Step-by-step explanation:

To solve this problem, we need to multiply add 15% of 4,000 back to 4,000.

First, change 15% into a decimal:

15% -> \frac{15}{100} -> 0.15

Next, multiply 4,000 by 0.15:

x= 4,000(0.15)

x=600

The last step is to add the 600 back to 4,000:

4,000 + 600 = 4,600

The population of Smallburg the following year was 4,600.

5 0
3 years ago
If exactly 194 people sign up for a charter flight, Leisure World Travel Agency charges $312/person. However, if more than 194 p
maw [93]

Title:

<h2>The revenue will be maximum for 253 passengers.</h2>

Step-by-step explanation:

Let, the number of passenger is x, which is more than 194.

In this case, the travel agency will charge [312 - (x - 194)] per passenger.

The total revenue will be x[312 - (x - 194)] = 506x - x^{2}.

As x is the variable here, we can represent the revenue function by R(x). Hence, R(x) = 506x - x^{2}.

The revenue will be maximum when \frac{d (506x - x^{2} )}{dx} = 0\\2x = 506\\x = 253.

6 0
3 years ago
Tan θ sin θ + sin θ = 0 . Solve the given equation.
VashaNatasha [74]
Here's a PDF file with the solution... Powered by Wolfram Mathematica
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4 0
3 years ago
Find the area of each figure. Pls, this is urgent, I will award brainliest.
Crazy boy [7]

Answer:

The area of the figure is;

A = 2,112 in²

Step-by-step explanation:

The given figure is a composite figure consisting of a rectangle AINE and a triangle AIL

The dimensions of the rectangle AINE are;

Length, L = 48 in.

Height, h = 32 in.

The area of the rectangle AINE, A₁ = Length, L × Height, h

∴ A = L × h = 48 in. × 32 in. = 1,536 in.²

The area of the triangle AIL, A₂ = 1/2 × Base × Height of the triangle

The base length of the triangle, L = IA = 48 in.

The height of the triangle, ht = 12 in.

∴ A₂ = L × ht

A₂ = 48 in. × 12 in. = 576 in.²

The area of the triangle AIL, A₂ = 576 in.²

The area of the figure, A = The area of the rectangle, A₁ + The area of the triangle, A₂

A = A₁ + A₂

∴ A = 1,536 in.² + 576 in.² = 2,112 in.²

The area of the figure, A = 2,112 in².

4 0
3 years ago
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