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2 years ago

Find xplease help!!

Mathematics

1 answer:

riadik2000 [5.3K]2 years ago

7 0

Answer: $9\sqrt{3}$

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Explanation:

For any 30-60-90 triangle, the short leg is always half the hypotenuse.

This makes the short leg to be 18/2 = 9 units long.

We then multiply this by $\sqrt{3}$ to get the length of the long leg.

$\text{long leg} = (\text{short leg})*\sqrt{3}\\\text{long leg} =9\sqrt{3}$

Or you could use the pythagorean theorem to solve $x^2+9^2 = 18^2$ and you should get $x = \sqrt{243} = 9\sqrt{3}$

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In an arithmetic sequence, the nth term an is given by the formula an=a1+(n−1)d, where a1 is the first term and d is the commo

Dmitry_Shevchenko [17]

Answer:

$a_{10} = \frac{10}{65536}$

Step-by-step explanation:

The first step to solving this problem is verifying if this sequence is an arithmetic sequence or a geometric sequence.

This sequence is arithmetic if:

$a_{3} - a_{2} = a_{2} - a_{1}$

We have that:

$a_{3} = 40, a_{2} = 10, a_{3} = \frac{5}{2}$

$a_{3} - a_{2} = a_{2} - a_{1}$

$\frac{5}{2} - 10 = 10 - 40$

$\frac{-15}{2} \neq -30$

This is not an arithmetic sequence.

This sequence is geometric if:

$\frac{a_{3}}{a_{2}} = \frac{a_{2}}{a_{1}}$

$\frac{\frac{5}[2}}{10} = \frac{10}{40}$

$\frac{5}{20} = \frac{1}{4}$

$\frac{1}{4} = \frac{1}{4}$

This is a geometric sequence, in which:

The first term is 40, so $a_{1} = 40$

The common ratio is $\frac{1}{4}$ , so $r = \frac{1}{4}$ .

We have that:

$a_{n} = a_{1}*r^{n-1}$

The 10th term is $a_{10}$ . So:

$a_{10} = a_{1}*r^{9}$

$a_{10} = 40*(\frac{1}{4})^{9}$

$a_{10} = \frac{40}{262144}$

Simplifying by 4, we have:

$a_{10} = \frac{10}{65536}$

3 0

3 years ago

on an airplane,there are two seats on the left side in each row and three seats on the right side.There are 90 seats on the righ

pantera1 [17]

Left side: (equation) 2/x=3/90 (multiply them together by cross multiplying. 90x2 divided by 3)
=60

Altogether: 90 (right) + 60 (left) =150 seats in total

4 0

3 years ago

Read 2 more answers

The altitude of a triangle is increasing at a rate of 1 cm/min while the area of the triangle is increasing at a rate of 2 cm2/m

Mnenie [13.5K]

Answer:

The base is reducing at a rate of 3.4cm per min.

Step-by-step explanation:

Let The Height of the Triangle, h

Area of the triangle = A

Area of a Triangle, $A= \frac{1}{2}bh$

When $A=190 cm^2, h=10cm$

$190= \frac{1}{2}*b*10\\b=38cm$

$\frac{dA}{dt}=\frac{1}{2}h\frac{db}{dt}+ \frac{1}{2}b\frac{dh}{dt}\\\frac{dh}{dt}=1 cm/min, \frac{dA}{dt}=2cm^2/min,$

$2=\frac{1}{2}*10*\frac{db}{dt}+ \frac{1}{2}*38*1\\2=5\frac{db}{dt}+19\\2-19=5\frac{db}{dt}\\-17=5\frac{db}{dt}\\\frac{db}{dt}=-\frac{17}{5} =-3.4 cm/min$

The base is reducing at a rate of 3.4cm per min.

8 0

2 years ago

I have to find the value of x please help me will give brainliest to correct answer

Semenov [28]

Answer:

C. x = 5

Step-by-step explanation:

48 = 7x + 13

-13 -13

35 = 7x

5 = x

7 0

2 years ago

<img src="https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx-5%7D" id="TexFormula1" title="\sqrt[3]{x-5}" alt="\sqrt[3]{x-5}" align="abs

sashaice [31]

Answer:

It cannot be solved furthur bro as the value of x is unspecified

6 0

3 years ago

Find xplease help!!​

Find xplease help!!