Answer:
<h2>A
pproximately 4824 games </h2>
Step-by-step explanation:
Given that the sales made are 4,567 ,5430, 3998, 5,220,and 4,906
the average is (4567+5430+3998+5220+4906)/5
=24121/5
=4824.2
in the month of august let the sales be x
average= (4567+5430+3998+5220+4906+x)/6
the average for march to july is 4824.2
4824.2= (4567+5430+3998+5220+4906+x)/6
24121+x=4824.2*6
24121+x=28945.2
x=28945.2-24121
x=4824.2
approximately 4824 games
Answer:
d = Sqrt 41 = 6.4
Step-by-step explanation:
d = sqrt [(x-x)^2 + (y-y)^2]
d = sqrt [(-7 - - 2)^2 + (7-3)^2]
d = sqrt[(-7+2)^2 + (4)^2]
d = sqrt [(-5)^2 + (4)^2]
d= sqrt (25 + 16)
d = sqrt 41 = 6.4
Answer:
Step-by-step explanation:
Because of the right angle (90 deg) in red, and the horizontal line on the bottom axis,
we know that :
49 + (1+5x) = 90
solving for x delivers x=8
1. The remaing area of the yard will be found as follows:
Area of the yard
A1=length*width=10x*15x=150x^2 yd^2
area of the fountain
A2=πr²
A2=π(4x)²
=50.266x^2
The remaining area will be:
A=150x^2-50.266x^2
A=99.735x^2 yd^2
2] Area left for bleachers, restrooms and other parts of the stadium will be as follows:
Area of the lot is:
A1=length*width
A1=8x×12x= 96x^2
Area of the field
A2=length×width
A2=3x×6x=18x^2
Hence the remaining area will be:
A1-A2
=96x^2-18x^2
=78x^2 sq. units
Answer:
this isnt math but the answer is D
Step-by-step explanation:
is this k12
