All categories

2 years ago

Send help djkhkjdhkhjksdhkh

Mathematics

1 answer:

Sedaia [141]2 years ago

3 0

Answer:

Step-by-step explanation:

I hope this helps you out!

You might be interested in

HELP ILL GIVE BRAINLISTTT!

olga nikolaevna [1]

Answer: √0.16

Step-by-step explanation:

√0.16 = 0.4

3 0

3 years ago

How to solve 10m-2/5=48/5

Romashka [77]

Answer:

Step-by-step explanation:

10m-2/5=9 and 3/5

10m-2/5=9.6 (where 9 and 3/5 is equal to 9.6)

50m-2=48 (i multiplied 10m by 5 and 9.6 by 5)

50m=50 ( i added 2 to both sides)

m=1 ( i divided by 50 to both sides to find m)

5 0

3 years ago

What is the equation of the following line? be sure to scroll down first to see all answer options

andreyandreev [35.5K]

Answer:

The equation for the following graph:

$y = -\frac{1}{5}x$

Step-by-step explanation:

- You first need to find the slope by using the slope formula:

$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$

(where $(x_{1},y_{1})$ is the first point and $(x_{2}, y_{2})$ is the second point)

-Use the given points $(0,0)$ and $(10, -2)$ from the graph for the formula:

$m = \frac{-2 - 0}{10 - 0}$

Then, you solve:

$m = \frac{-2 - 0}{10 - 0}$

$m = -\frac{1}{5}$

After you have found the slope, use the slope $-\frac{1}{5}$ and the first point $(0,0)$ for the point-slope formula:

$y - y_{1} = m ( x - x_{1})$

(where $m$ is the slope and $(x_{1}, y_{1})$ is the first point)

$y - 0 = -\frac{1}{5} ( x - 0)$

Then, you solve:

$y - 0 = -\frac{1}{5} ( x - 0)$

$y - 0 = -\frac{1}{5}x - 0$

$y - 0 + 0 = -\frac{1}{5} - 0 + 0$

$y = -\frac{1}{5}x$

So, the equation for the following graph is $y = -\frac{1}{5}x$ .

7 0

2 years ago

If a^2+3a+9=0, What is a^3?

kifflom [539]

i dunooo i dont even nooooo

7 0

3 years ago

Consider the following set of equations, where s, s0, x and r have units of length, t has units of time, v has units of velocity

Anna11 [10]

Answer:

Step-by-step explanation:

For an equation to be dimensionally correct the dimension of quantities on both sides of equation must be same.

Also, two physically quantities can only be added or subtracted only when their dimension are same.

here all option are dimensionally correct except the 5th option where

dimension of t= [T] whereas dimension of a/v is $\frac{LT^{-2}}{LT^{-1}}$

= T^{-1}

since, the dimension of quantities on either sides of equation are not the same the equation is dimensionally is incorrect.

8 0

3 years ago