Let ‘s’ be the son’s age 12 years ago.
Let ‘f’ be the father’s current age.
4 years ago, the son was:
s-4
So, his father is currently:
3(s-4)
=
3s-12
Therefore:
f = 3s-12
In twelve years, the son will be:
s+12
And the father will be:
f+12
This can also be written as:
3s-12+12 as the fathers younger age would be f = 3s+12
=
3s
So, we know that s+12 is half the fathers current age, meaning the father is currently 2(s+12) which is equivalent to 2s+24. Also, we know that the father is currently 3 times the sons age 12 years ago, so 3s (proven by the calculations we made above). Therefore, 2s+24=3s which means 24=s. We can then substitute this, and we will receive 24+12 = 36
Son’s current age: 36
We then substitute the son’s age 12 years ago into 2s+24 to give us the father’s age.
2(24)+24 = 72
Father’s current age: 72
Answer:
So you would not be carried away by the tides
Step-by-step explanation:
hope this is what u want
Answer:
(A) There should have been 5 outcomes of HT
(B) The experimental probability is greater than the theoretical probability of HT.
Step-by-step explanation:
Given
-- Sample Space
--- Sample Size
Solving (a); theoretical outcome of HT in 20 tosses
First, calculate the theoretical probability of HT
Multiply this by the number of tosses
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Solving (b); experimental probability of HT
Here, we make use of the table
---- Experimental Probability
In (a), the theoretical probability is:
---- Experimental Probability
By comparison;
Answer:
2x + 5
Step-by-step explanation:
I am assuming you are talking about a linear function. If it is, then the equation would be:
2x + 5.
Hope this helps!
Answer:
b,c,d
Step-by-step explanation:
