The alkali metals, which occupy group 1 of the periodic table. This is because the valence shells of these elements have only 1 electron, so easily form an ionic bond with a non-metal compound by donating this. A cation is formed by this donation, since there is one fewer electron orbiting the nucleus than there is in the atomic form - conversely an anion is formed when an atom gains an extra electron to become negatively charged.
The cell notation for the voltaic cell that incorporates the redox reaction Mg(s) + Sn²⁺(aq) → Mg²⁺(aq) + Sn(s) is Mg(s)|Mg²⁺(aq)║Sn²⁺(aq)|Sn(s).
The cell notation for a voltaic cell is the following:
anode ║ cathode
The anode is where the oxidation reaction takes place and the cathode is where the reduction happens.
The given reaction is:
Mg(s) + Sn²⁺(aq) → Mg²⁺(aq) + Sn(s)
We can see that <u>magnesium </u>is <u>oxidizing</u> (it is losing electrons) and that <u>tin </u>is <u>reducing</u> (it is gaining electrons).
These two processes can be represented in the following half-reactions:
Oxidation: Mg(s) → Mg²⁺(aq)
Reduction: Sn²⁺(aq) → Sn(s)
Which in <u>cell notation</u> is:
Anode: Mg(s)|Mg²⁺(aq)
Cathode: Sn²⁺(aq)|Sn(s)
Hence, the <u>notation</u> for the <u>voltaic cell</u> is:
Mg(s)|Mg²⁺(aq)║Sn²⁺(aq)|Sn(s)
Therefore, the cell notation for the voltaic cell with the given reaction is Mg(s)|Mg²⁺(aq)║Sn²⁺(aq)|Sn(s).
Learn more about voltaic cells here:
I hope it helps you!
Answer:
Inflamabilidad y características de la llama: el hidrógeno es inflamable en el aire en un amplio rango de concentraciones y arde, en ausencia de impurezas, con una llama casi invisible. Energía de ignición: el hidrógeno puede entrar en ignición con una cantidad de energía muy pequeña.
Explanation:
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The answer is A.
The molecules in the air located.......below.
The balanced equation for the acid base reaction is as follows
NaOH + HCl ---> NaCl + H₂O
stoichiometry of NaOH to HCl is 1:1
the number of NaOH moles reacted - 0.200 mol/L x 0.0250 L = 0.005 mol
according to molar ratio
number of NaOH moles reacted = number of HCl moles reacted
therefore number of HCl moles - 0.005 mol
volume of 30.0 mL contains 0.005 mol
therefore 1000 mL contains - 0.005 mol / 0.030 L = 0.167 M
concentration of HCl is 0.167 M