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Dmitriy789 [7]
3 years ago
6

In a two-stroke engine oil injection system:

Engineering
1 answer:
nevsk [136]3 years ago
6 0
My car bf said it’s D
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A wastewater plant discharges a treated effluent (w) with a flow rate of 1.1 m^3/s, 50 mg/L BOD5 and 2 mg/L DO into a river (s)
4vir4ik [10]

A wastewater plant discharges a treated effluent (w) with a flow rate of 1.1 m^3/s, 50 mg/L BOD5 and 2 mg/L DO into a river (s) with a flow rate of 8.7 m^3/s, 6 mg/L BOD5 and 8.3 mg/L DO. Both streams are at 20°C. After mixing, the river is 3 meters deep and flowing at a velocity of 0.50 m/s. DOsat for this river is 9.0 mg/L. The deoxygenation constant is kd= 0.20 d^-1 and The reaction rate constant k at 20 °C is 0.27 d^-1.

The answer therefore would be the number 0.27 divided by two and then square while getting the square you would make it a binomial.

I wont give the answer but the steps

Your Welcome

8 0
4 years ago
1. A thin-walled cylindrical pressure vessel is capped at the end and is subjected to an internal pressure (p). The inside diame
Vesna [10]
I DONT KNOW OKAY UGHHH
6 0
3 years ago
A ____ is marked by two sets of double yellow lines, with each set having a broken line on the inside, and a solid line on the o
Vitek1552 [10]

Answer:

  center left-turn lane

Explanation:

A <em>center left turn lane</em> will be marked as described. The arrows, if present, generally indicate that left turns are permitted from the lane with these markings.

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If the double yellow lines are solid, they are considered to be a "barrier" and are not to be crossed.

7 0
3 years ago
Read 2 more answers
In the last 5 meters of braking, you lose ___ of your speed.
expeople1 [14]

Answer:

answer is

a)

3/4

Explanation:

In the last 5 meters of braking, you lose 3/4 of your speed.

5 0
3 years ago
A residential heat pump has a coefficient of performance of 1.49 How much heating effect, in kJ/h, will result when 4 kW is supp
AfilCa [17]

Answer:

21.456 kJ/h

Explanation:

See the figure attached. In this case  

W_{cycle} = 4 kW

Q_{out} = \text{heating effect}

Coefficient of performance in heat pump is defined by

COP = \frac{Q_{out}}{W_{cycle}}

Q_{out} =COP*W_{cycle}

Q_{out} =1.49*4 \, W

Q_{out} = 5.96 \, W

Now it is necessary to change units, remember that Watt (W) is defined as J/s

Q_{out} = 5.96 \frac{J}{s} \frac{3600s}{1 h} \frac{1 kJ}{1000 J}

Q_{out} = 21.456 \frac{kJ}{h}

3 0
4 years ago
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