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2 years ago

What's the best way to find the load capacity of a crane?

Engineering

1 answer:

Korvikt [17]2 years ago

5 0

Answer:

weight

Explanation:

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Which of these cars traveled faster during time interval please show solution

Mazyrski [523]

Answer:

I think D is correct

Explanation:

C is decreasing function, probably worst

A is arctan -> in radian, the rate of increasing is very slow-> second worst

B(14) = ln(9*14) = 4.8

D(14) = sqrt(8+14^2)=14.2

3 0

3 years ago

A large fraction of the thermal energy generated in the engine of a car is rejected to the air by the radiator through the circu

Rina8888 [55]

Open system because there is mass (water) flowing through the system of interest (radiator)

5 0

2 years ago

One AA battery in a flashlight stores 9400 J. The three LED flashlight bulbs consume 0.5 W. How many hours will the flashlight l

Effectus [21]

Answer:

time = 5.22 hr

Explanation:

Given data:

Energy of battery = 9400 J

Power consumed by three led bulb is 0.5 watt

we know Power is give as

$Power = \frac{ energy}{time}$

plugging all value and solve for time

$time = \frac{energy}{power}$

$time = \frac{9400}{0.5}$

time = 18,800 sec

in hour

1 hour = 3600 sec

therefore in 18,800 sec

$time = \frac{18800}{3600} = 5.22 hr$

7 0

3 years ago

I am having trouble understanding how I got these wrong on my test. Is there something I am missing with xor?

GuDViN [60]

Answer:

your answer is correct

Explanation:

You have the correct mapping from inputs to outputs. The only thing your teacher may disagree with is the ordering of your inputs. They might be written more conventionally as ...

A B Y

0 0 1

0 1 0

1 0 0

1 1 1

That is, your teacher may be looking for the pattern 1001 in the last column without paying attention to what you have written in column B.

8 0

2 years ago

A strip ofmetal is originally 1.2m long. Itis stretched in three steps: first to a length of 1.6m, then to 2.2 m, and finally to

andreyandreev [35.5K]

Answer:

strains for the respective cases are

0.287

0.318

0.127

and for the entire process 0.733

Explanation:

The formula for the true strain is given as:

$\epsilon =\ln \frac{l}{l_{o}}$

Where

$\epsilon =$ True strain

l= length of the member after deformation

$l_{o} =$ original length of the member

Now for the first case we have

l= 1.6m

$l_{o} = 1.2m$

thus,

$\epsilon =\ln \frac{1.6}{1.2}$

$\epsilon =0.287$

similarly for the second case we have

l= 2.2m

$l_{o} = 1.6m$ (as the length is changing from 1.6m in this case)

thus,

$\epsilon =\ln \frac{2.2}{1.6}$

$\epsilon =0.318$

Now for the third case

l= 2.5m

$l_{o} = 2.2m$

thus,

$\epsilon =\ln \frac{2.5}{2.2}$

$\epsilon =0.127$

Now the true strain for the entire process

l=2.5m

$l_{o} = 1.2m$

thus,

$\epsilon =\ln \frac{2.5}{1.2}$

$\epsilon =0.733$

6 0

2 years ago