Answer:
Change in kinetic energy=-513.652 KJ
Change in potential energy=431.64KJ
Explanation:
We are given that
Mass of an automobile , m=1100 kg
Initial speed, u=110 km/h=
Where 
Height , 

Final speed, v=0
Change in kinetic energy,


Where 1 KJ=1000 J
Change in potential energy,
Initially height, h1=0
Using the formula



3-SAT ≤p TSP
If P ¹ NP, then no NP-complete problem can be solved in polynomial time.
both the statements are true.
<u>Explanation:</u>
- 3-SAT ≤p TSP due to any complete problem of NP to other problem by exits of reductions.
- If P ¹ NP, then 3-SAT ≤p 2-SAT are the polynomial time algorithm are not for 3-SAT. In P, 2-SAT is found, 3- SAT polynomial time algorithm implies the exit of reductions. 3 SAT does not have polynomial time algorithm when P≠NP.
- If P ¹ NP, then no NP-complete problem can be solved in polynomial time. because for the NP complete problem individually gets the polynomial time algorithm for the others. It may be in P for all the problems, the implication of latter is P≠NP.
Answer: (D: Tweezers)
A basic first aid kit is always good to have in case of an emergency. The typical items found in a first aid kit are pain reliever, tweezers, alcohol wipes, gloves, antiseptic, medical tape, sterile gauze, insect bite swaps, triple-antibiotic ointment, hydrogen peroxide, bandage scissors, instant cold compresses, and of course bandages. There are various types of bandages that can be included; elastic bandages, adhesive bandages, and triangular bandages for starters.
Explanation:
Answer:
Electroosmotic velocity will be equal to 
Explanation:
We have given applied voltage v = 100 volt
Length of capillary L = 5 mm = 0.005 m
Zeta potential of the capillary surface 
Dielectric constant of glass is between 5 to 10 here we are taking dielectric constant as 
Viscosity of glass is 
Electroosmotic velocity is given as 

So Electroosmotic velocity will be equal to 
Answer:
a) 70.29 %
b) 37%
Explanation:
percent reduction can be found from:
PR = 100*(π(do/2)^2-π(df/2)^2)/π(do/2)^2
= 100*(π(11.34/2)^2-π(6.21/2)^2)/π(11.34/2)^2
=70.29 %
percent elongation can be found from:
EL =L_f - Lo/Lo*100
= (73.17 -53.3/53.3)*100
= 37%