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borishaifa [10]
3 years ago
10

A 1/20 scale model of a wing is used to determine forces on the actual airplane. the 1/20 scale refers to the:_____

Engineering
2 answers:
Nataly_w [17]3 years ago
7 0

Answer:

a. lengths.

Explanation:

The scale can be said to be a representation of the model as regards the prototype. The prototype is the machine. Using a 1:20 scale tells us that the model is 1/20 times the magnitude of the length of this machine. So if the length of the side of the machine = 20m then we would have the length of the model as 1. (1/20x20 = 1)

Therefore the scale is the length and option a is correct

Kryger [21]3 years ago
5 0

Answer:

A Lengths

Explanation:

you make a model to show an object too large to test and too expensive to test

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A 500-km, 500-kV, 60-Hz, uncompensated three-phase line has a positivesequence series impedance. z = 5 0.03 1 + j 0.35 V/km and
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Answer:

A) 282.34 - j 12.08 Ω

B) 0.0266 + j 0.621 / unit

C)

A = 0.812 < 1.09° per unit

B =  164.6 < 85.42°Ω  

C =  2.061 * 10^-3 < 90.32° s

D =  0.812 < 1.09° per unit

Explanation:

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positive sequence shunt admittance ( Y ) = j4.4*10^-6 S/km

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hence Zc = 282.34 - j 12.08 Ω

B) Calculate  gl

gl = \sqrt{zy} * d  

 d = 500

 z = 0.03 i  + j 0.35

 y = j4.4*10^-6 S/km

gl =  \sqrt{0.03 i  + j 0.35*  j4.4*10^-6}  * 500

   = \sqrt{1.5456*10^{-6} < 175.1^0} * 500

   = 0.622 < 87.55 °

gl = 0.0266 + j 0.621 / unit

C) exact ABCD parameters for this line

A = cos h (gl) . per unit  =  0.812 < 1.09° per unit ( as calculated )

B = Zc sin h (gl) Ω  = 164.6 < 85.42°Ω  ( as calculated )

C = 1/Zc  sin h (gl) s  =  2.061 * 10^-3 < 90.32° s ( as calculated )

D = cos h (gl) . per unit = 0.812 < 1.09° per unit ( as calculated )

where :  cos h (gl)  = \frac{e^{gl} + e^{-gl}  }{2}

             sin h (gl) = \frac{e^{gl}-e^{-gl}  }{2}

     

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