1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
borishaifa [10]
3 years ago
10

A 1/20 scale model of a wing is used to determine forces on the actual airplane. the 1/20 scale refers to the:_____

Engineering
2 answers:
Nataly_w [17]3 years ago
7 0

Answer:

a. lengths.

Explanation:

The scale can be said to be a representation of the model as regards the prototype. The prototype is the machine. Using a 1:20 scale tells us that the model is 1/20 times the magnitude of the length of this machine. So if the length of the side of the machine = 20m then we would have the length of the model as 1. (1/20x20 = 1)

Therefore the scale is the length and option a is correct

Kryger [21]3 years ago
5 0

Answer:

A Lengths

Explanation:

you make a model to show an object too large to test and too expensive to test

You might be interested in
For this question you must write a java class called Rectangle and a client class called RectangleClient. The partial Rectangle
Alex Ar [27]

Answer:

Java program is given below. You can get .class after you execute java programs, You can attach those files along with .java classes given , Those .class files are generated ones.

Explanation:

//Rectangle.java class

public class Rectangle {

private int x;

private int y;

private int width;

private int height;

// constructs a new Rectangle with the given x,y, width, and height

public Rectangle(int x, int y, int w, int h)

{

this.x=x;

this.y=y;

this.width=w;

this.height=h;

}

// returns the fields' values

public int getX()

{

return x;

}

public int getY()

{

return y;

}

public int getWidth()

{

return width;

}

public int getHeight()

{

return height;

}

// returns a string such as “Coordinate is (5,12) and dimension is 4x8” where 4 is width and 8 is height. public String toString()

public String toString()

{

String str="";

//add x coordidate , y-coordinate , width, height and area to str and return

str+="Coordinate is ("+x+","+y+")";

str+=" and dimension is : "+width+"x"+height;

str+=" Area is "+(width*height);

return str;

}

public void changeSize(int w,int h)

{

width=w;

height=h;

}

}

======================

//main.java

class Main {

public static void main(String[] args) {

//System.out.println("Hello world!");

//create an object of class Rectangle

Rectangle rect=new Rectangle(5,12,4,8);

//print info of rect using toString method

System.out.println(rect.toString());

//chamge width and height

rect.changeSize(3,10);

//print info of rect using toString method

System.out.println(rect.toString());

}

}

==========================================================================================

//Output

Coordinate is (5,12) and dimension is : 4x8 Area is 32

Coordinate is (5,12) and dimension is : 3x10 Area is 30

========================================================================================

6 0
3 years ago
Your program will be a line editor. A line editor is an editor where all operations are performed by entering commands at the co
soldier1979 [14.2K]

Answer:

Java program given below

Explanation:

import java.util.*;

import java.io.*;

public class Lineeditor

{

private static Node head;

 

class Node

{

 int data;

 Node next;

 public Node()

 {data = 0; next = null;}

 public Node(int x, Node n)

 {data = x; next =n;}

}

 

public void Displaylist(Node q)

 {if (q != null)

       {  

        System.out.println(q.data);

         Displaylist(q.next);

       }

 }

 

public void Buildlist()

  {Node q = new Node(0,null);

       head = q;

       String oneLine;

       try{BufferedReader indata = new

                 BufferedReader(new InputStreamReader(System.in)); // read data from terminals

                       System.out.println("Please enter a command or a line of text: ");  

          oneLine = indata.readLine();   // always need the following two lines to read data

         head.data = Integer.parseInt(oneLine);

         for (int i=1; i<=head.data; i++)

         {System.out.println("Please enter another command or a new line of text:");

               oneLine = indata.readLine();

               int num = Integer.parseInt(oneLine);

               Node p = new Node(num,null);

               q.next = p;

               q = p;}

       }catch(Exception e)

       { System.out.println("Error --" + e.toString());}

 }

public static void main(String[] args)

{Lineeditor mylist = new Lineeditor();

 mylist.Buildlist();

 mylist.Displaylist(head);

}

}

7 0
3 years ago
4) A steel tape is placed around the earth at the equator when the temperature is 0 C. What will the clearance between the tape
snow_lady [41]

Answer:

2102.1 m

Explanation:

Temperature at the equator = 0⁰

Radius of the earth = 6.37x10⁶

Required:

We how to find out what the clearance between tape and ground would be if temperature increases to 30 degrees.

Final temperature = ∆T = 303-273 = 30

S = 11x10^-6

The clearance R = Ro*S*∆T

=6.37x10⁶x 11x10^-6x30

= 2102.1m

Or 2.102 kilometers

Thank you

4 0
2 years ago
water at 20c discharges from a stroke tank through a 150m length of horizontal pipe. The pipe is smooth and has a diameter of 75
inessss [21]

Answer:

The dept of the water needed is 26.11m

Explanation:

Given the following parameters:

Length of the pipe = 150m

Diameter of the pipe = 75mm = 0.75m

Volumetric flow rate 1m^{3}/s

Knowing that:

Volumetric flowrate = area (A) * Velocity(V)

==> 0.1 = A*V                              *Knowing that V = \sqrt{2gh}

==> 0.1  = \frac{\pi }{4}* (0.075)^{2} * \sqrt{2gh}

==> h = 26.11m

Hence, the dept of water needed to produce a volumetric flow rate of 1m^{3}/s is 26.11m.

7 0
3 years ago
When a 60 Hz sinusoidal voltage is applied to the input of a half-wave rectifier, the output frequency is
Ludmilka [50]

Answer:

120 Hz

Explanation:

Given that a 60 Hz sinusoidal voltage is applied to the input of a half-wave rectifier, what will be the output frequency ?

Ideally, the supply frequency will be equal to the ripple frequency.

But in a half - way rectifier, the out put frequency is twice the input sinusoidal voltage frequency.

The output frequency = 2 × 60

Output frequency = 120 Hz

Therefore, When a 60 Hz sinusoidal voltage is applied to the input of a half-wave rectifier, the output frequency is 120 Hz.

4 0
3 years ago
Other questions:
  • Find the linear speed of the bottom of a test tube in a centrifuge if the centripetal acceleration there is 5.4×104 times the ac
    6·1 answer
  • Please help me fast, I don’t have time
    15·1 answer
  • A cylindrical metal specimen having an original diameter of 12.8 mm and gauge length of 50.80 mm is pulled in tension until frac
    9·1 answer
  • Suppose you are implementing a relational employee database, where the database is a list of tuples formed by the names, the pho
    14·1 answer
  • A large prime number isP = 232582657 - 1
    8·1 answer
  • Link AB is to be made of a steel for which the ultimate normal stress is 65 ksi. Determine the cross-sectional area of AB for wh
    14·1 answer
  • Which of the following is NOT true concerning the color of minerals? A. Some minerals have a consistent color, but many have a r
    13·1 answer
  • Three 1.83 in. diameter bolts are used to connect the axial member to the support in a double shear connection. The ultimate she
    8·1 answer
  • If the 2007 recession affected the green building materials market less seriously than other parts of the construction market, t
    12·2 answers
  • How are sedimentary - gravity flows different from fluid - gravity flows
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!