The EMV - Ending Market Value is given as:
$2,400,000.
<h3>How is the EMV Arrived At?</h3>
The EMV is given as:
BMV x (i + r); Where
BMV is the Beginning Market Value; and
r is the interest rateor percentage given.
Hence the EMV = 2,000,000 x ( 1 + 20%)
= 2,000,000 x 1.2
= $ 2, 400,000.
It is to be noted that the BMV is the Beginning Market Value which is the value of an investment at the start of the business period.
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Answer:
=4/5 because I'm not going to go back in a year meaning that they are you are
Engineering ethics is not without abstraction, but in contrast with computing, it is animated by a robust and active movement concerned with the seamless identification of ethics with practice.
<h3 /><h3>What is engineering?</h3>
This is a branch of science and technology concerned with the design, building, and use of engines, machines, and structures that uses scientific principles.
Comparing ethics in engineering and ethics in computing:
- Engineering ethics are a set of rules and guidelines. While computing ethics deals with procedures, values and practices.
- In engineering ethics, engineers must adhere to these rules as a moral obligation to their profession While in computing ethics, the ethics govern the process of consuming computer technology.
- Following these ethics for the two professions will NOT cause damage, but disobeying them causes damage.
Some practical examples in the computing field:
- Avoid using the computer to harm other people such as creating a bomb or destroying other people's work.
- Users also should not use a computer for stealing activities like breaking into a bank or company.
- Make sure a copy of the software had been paid for by the users before it is used.
Some practical examples in the engineering field:
- Integrity for oneself.
- Respect for one another.
- Pursuit of excellence and accountability.
Hence, Engineering ethics is the field of system of moral principles that apply to the practice of engineering and following them is important to the profession.
Read more about <em>engineering</em> here:
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Answer:
1.0MG
Explanation:
to solve this problem we use this formula
S₀-S/t = ksx --- (1)
the values have been given as
concentration = S₀ = 250mg
effluent concentration = S= 10mg
value of K = 0.04L/day
x = 3000 mg
when we put these values into this equation,
250-10/t = 0.04x10x3000
240/t = 1200
we cross multiply from this stage
240 = 1200t
t = 240/1200
t = 0.2
remember the question says that 5MGD is required to be treated
so the volume would be
v = 0.2x5
= 1.0 MG
Answer: 1.137*10^7 Btu/h.
Explanation:
Given data:
Efficiency of the plant = 4.5percent
Net power output of the plant = 150kw
Solution:
The required collection rate
QH = W/n
= 150/0.045 * 0.94782/ 1 /60 */60 Btu/h.
= 3333.333 *3412.152Btu/h.
= 11373840 Btu/h
= 1.137*10^7 Btu/h.
