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just olya [345]
2 years ago
10

How many molecules are there in 122 grams of NO2

Chemistry
1 answer:
AnnyKZ [126]2 years ago
3 0
Thus, there are 1.47 × 10^(23) molecules present in 122 grams of NO2.
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What is the reactivity trend of halogens?
RSB [31]
Reactivity trends of halogen:

1) Melting point and boiling points increased down the
group

2) Colour becomes darker.
E.g. Fluorine (pale yellow)
Chlorine (yellowish-green)
Bromine (reddish-brown)
Iodine (purplish-black)
Astatine (black)

3) The reactivity decreases down the group.
Reactivity:
F > Cl > Br > I > At
3 0
3 years ago
How much heat is required to warm 1.50L of water from 25.0C to 100.0C? (Assume a density of 1.0g/mL for the water.)
Masteriza [31]

<u>Answer:</u> The amount of heat required to warm given amount of water is 470.9 kJ

<u>Explanation:</u>

To calculate the mass of water, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

Density of water = 1 g/mL

Volume of water = 1.50 L = 1500 mL    (Conversion factor:  1 L = 1000 mL)

Putting values in above equation, we get:

1g/mL=\frac{\text{Mass of water}}{1500mL}\\\\\text{Mass of water}=(1g/mL\times 1500mL)=1500g

To calculate the heat absorbed by the water, we use the equation:

q=mc\Delta T

where,

q = heat absorbed

m = mass of water = 1500 g

c = heat capacity of water = 4.186 J/g°C

\Delta T = change in temperature = T_2-T_1=(100-25)^oC=75^oC

Putting values in above equation, we get:

q=1500g\times 4.186J/g^oC\times 75^oC=470925J=470.9kJ

Hence, the amount of heat required to warm given amount of water is 470.9 kJ

6 0
3 years ago
Why is the earth often referred to as the blue planet
Vilka [71]

Most of the surface of the earth is covered with water and looks blue from space.

7 0
3 years ago
Read 2 more answers
If 287 mL of a 1.6 M glucose solution is diluted to 412 mL , what is the molarity of the diluted solution
satela [25.4K]

Answer:

The answer to your question is 1.11 M

Explanation:

Data

volume 1 = 287 ml

concentration 1 = 1.6 M

volume 2= 412 ml

concentration 2 = ?

Formula

               Volume 1 x concentration 1 = Volume 2 x concentration 2

Solve for concentration 2

          concentration 2 = (volume 1 x concentration 1) / volume 2

Substitution

          concentration 2 = (287 x 1.6) / 412

Simplification

          concentration 2 = 459.2 / 412

Result

           concentration 2 = 1.11 M  

5 0
3 years ago
The amount of space tgat matter occupies is referred to as...
Marrrta [24]
It is either mass or volume
4 0
2 years ago
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