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Andre45 [30]
3 years ago
7

Which part(s) of a microscope forms an enlarged image of a specimens?

Chemistry
2 answers:
Damm [24]3 years ago
6 0
D. The objective lenses

The objective lens magnifies the specimen to produce a real image that is projected to the ocular. This real image is magnified by the ocular lens to produce the virtual image seen by your eye.
olchik [2.2K]3 years ago
3 0
It would be the objective lenses
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Consider the reaction for the decomposition of hydrogen disulfide: 2H2S(g)⇌2H2(g)+S2(g), Kc = 1.67×10−7 at 800∘C A 0.500 L react
trasher [3.6K]

Answer:

Molar concentration of S₂ is 1.77×10⁻⁶M

Explanation:

For the reaction:

2H₂S(g) ⇄ 2H₂(g) + S₂(g)

The equilibirum constant, K, is defined as:

K = \frac{[S_2][H_2]^2}{[H_2S]^2}<em>(1)</em>

Concentrations in equilibirum are:

[H₂S] : 0,163/0.500L - X

[H₂] : 0,0500/0.500L + X

[S₂] : X

Replacing the concentrations and the equilibrium value in (1):

K = \frac{[X][0.1+X]^2}{[0326-X]^2}

1.67x10⁻⁷ = X (X² + 0.2X + 0.01) / (X² -0.652X + 0.106)

1.67x10⁻⁷X² - 1.09x10⁻⁷X + 1.77x10⁻⁸ = X³ + 0.2X² + 0.01X

0 =  X³ + 0.2X² + 0.01X - 1.77x10⁻⁸

Solving for X:

X = 1.77×10⁻⁶

As [S₂] = X, <em>molar concentration of S₂ is 1.77×10⁻⁶M</em>

I hope it helps!

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