Answer:
Q = -811440 J
Explanation:
Given data:
Mass of oil = 2.76 Kg (2.76× 1000 = 2760 g)
Initial temperature = 191 °C
Final temperature = 23°C
Specific heat capacity of oil = 1.75 J/g.°C
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 23°C - 191 °C
ΔT = -168°C
Q = 2760 g ×1.75 J/g.°C ×-168°C
Q = -811440 J
Negative sign show heat is released.
Copper(I) compounds in aqueous solutions are unstable and disproportionate:
Cu₂SO₄ = Cu + CuSO₄
Necessary for dissolution of non-aqueous solvent.
M(Cu₂SO₄)=223.16 g/mol
m(Cu₂SO₄)=14.1 g
v=0.250 L
n(Cu₂SO₄)=m(Cu₂SO₄)/M(Cu₂SO₄)
c=n(Cu₂SO₄)/v=m(Cu₂SO₄)/(vM(Cu₂SO₄))
c=14.1/(0.250*223.16)=0.253 mol/L
0.253 M
The answer to this question is:
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Hope this helped, Laffertytyler20
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The answer to this question is A
The answer is 232 plus 450
