Answer:
See Explanation
Explanation:
Elements in group fourteen are mostly known to form compounds in which there are four electron domains leading to a tetrahedral electron domain geometry.
However, the presence of lone pairs affects the shape of the molecule. SnCl3− has four electron domains, three of them are bond pairs while one is a lone pair. The shape of the molecule is based on a tetrahedron, however the observed geometry is trigonal pyramidal due to the presence of the lone pair. Its bond angle is now less than the predicted 109 degrees.
Answer: 8 Moles of Oxygen
Explanation: The formula shows that there are (exactly) 4 oxygen atoms in each mole or formula unit. Therefore 4 * 2.00 = 8.
The reaction is low b/c of the tempature. that's why.
Answer:
Option a.
0.01 mol of CaCl₂ will have the greatest effect on the colligative properties, because it has the biggest i
Explanation:
To determine which of the solute is going to have a greatest effect on colligative properties we have to consider the Van't Hoff factor (i)
These are the colligative properties:
ΔP = P° . Xm . i → Lowering vapor pressure
ΔT = Kb . m . i → Boiling point elevation
ΔT = Kf . m . i → Freezing point depression
π = M . R . T → Osmotic pressure
Van't Hoff factor are the numbers of ions dissolved in the solution. For nonelectrolytes, the i values 1.
CaCl₂ and KNO₃ are two ionic solutes. They dissociate as this:
CaCl₂ → Ca²⁺ + 2Cl⁻
We have 1 mol of Ca²⁺ and 2 chlorides, so 3 moles of ions → i = 3
KNO₃ → K⁺ + NO₃⁻
We have 1 mol of K⁺ and 1 mol of nitrate, so 2 moles of ions → i = 2
Option a, is the best.
Salt crystals are shaped like cubes. Salt is part of the isometric crystal system.
