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lana66690 [7]
3 years ago
13

A restaurant offers hamburgers with one, two, or three patties. Let XXX represent the number of patties a randomly chosen custom

er orders on their hamburger. Based on previous data, here's the probability distribution of XXX along with summary statistics: X=\text{\# of patties}X=# of pattiesX, equals, start text, \#, space, o, f, space, p, a, t, t, i, e, s, end text 111 222 333 P(X)P(X)P, left parenthesis, X, right parenthesis 0.400.400, point, 40 0.500.500, point, 50 0.100.100, point, 10 Mean: \mu_X=1.7μ X ​ =1.7mu, start subscript, X, end subscript, equals, 1, point, 7 Standard deviation: \sigma_X\approx0.67σ X ​ ≈0.67sigma, start subscript, X, end subscript, approximately equals, 0, point, 67
Mathematics
1 answer:
Alexandra [31]3 years ago
6 0

Answer:

3.4$     1.34 $

Step-by-step explanation:

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Painting USA is cheaper. They cost $700 dollars. The other place costs $1,000 dollars

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There are 7 7/8 cups of skittles in a Jar. If 2 1/4 cups are used for a party, how many skittes are left in the jar?
maw [93]
2 1/4 = 2 2/8. So, simply subtract 7 7/8 - 2 2/8 to get your final answer of 5 5/8
4 0
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Chứng minh mệnh đề sau bằng phương pháp phản chứng:
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Which language is this ?????

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3 years ago
Sam drinks water at an incredible rate. She drinks 2 1/5 liters of water every 3/4 of an hour. Sam drinks water at a constant ra
lora16 [44]

Answer:

2.9 litres

or

2 14/15 litres

Step-by-step explanation:

To determine the amount of water Sam drinks in an hour, divide the total amount drunk by the number of hours

Amount drank in an hour = total litres drunk / time

2\frac{1}{5} ÷ \frac{3}{4}

\frac{11}{5} × \frac{4}{3} = \frac{44}{15} = 2\frac{14}{15} litres

7 0
3 years ago
Temperature transducers of a certain type are shipped in batches of 50. A sample of 58 batches was selected, and the number of t
andrew11 [14]

Answer:

a) X        Freq.         Rel Freq.

__________________________

0           7              (7/58) = 0.121

1            10            (10/58)=0.172

2           13            (13/58) =0.224

3           14            (14/58)=0.241

4           6              (6/58)=0.103

5           3              (3/58)=0.052

6           3              (3/58)=0.052

7            1              (1/58) =0.017

8            1              (1/58)=0.017

_________________________

Total     58                 1.00

b) \frac{7+10+13+14+6}{58}= \frac{50}{58}=0.862

Step-by-step explanation:

Assuming this question: Temperature transducers of a certain type are shipped in batches of 50. A sample of 60 batches was selected, and the number of transducers in each batch not conforming to design specifications was determined, resulting in the following data:

2,1,2,4,0,1,3,2,0,5,3,3,1,3,2,4,7,0,2,3,

0,4,2,1,3,1,1,3,4,2,3,2,2,8,4,5,1,3,1,

5,0,2,3,2,1,0,6,4,2,1,6,0,3,3,3,6,2,3

(a) Determine frequencies and relative frequencies for the observed values of x = number of nonconforming transducers in a batch. (Round your relative frequencies to three decimal places.)

For this case first we order the dataset on increasing way and we got:

0 0 0 0 0 0 0

1 1 1 1 1 1 1 1 1 1

2 2 2 2  2 2 2 2 2 2 2 2 2

3 3 3 3 3 3 3 3 3 3 3 3  3 3

4 4 4 4 4 4

5 5 5

6 6 6

7

8

And we can construct the following table:

X        Freq.         Rel Freq.

__________________________

0           7              (7/58) = 0.121

1            10            (10/58)=0.172

2           13            (13/58) =0.224

3           14            (14/58)=0.241

4           6              (6/58)=0.103

5           3              (3/58)=0.052

6           3              (3/58)=0.052

7            1              (1/58) =0.017

8            1              (1/58)=0.017

_________________________

Total     58                 1.00

(b) What proportion of batches in the sample have at most four nonconforming transducers? (Round your answer to three decimal places.)

For this case this proportion would be:

\frac{7+10+13+14+6}{58}= \frac{50}{58}=0.862

4 0
3 years ago
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