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Artyom0805 [142]
3 years ago
15

Help me out with this pe question plz :c

Physics
2 answers:
blagie [28]3 years ago
6 0

Answer:

the first one is a group 1 and the second one is d all of the above

Explanation:

yaroslaw [1]3 years ago
3 0

Answer:

all of the above

Explanation:

all of them improve your cardio

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As a car drives with its tires rolling freely without any slippage, the type of friction acting between the tires and the road i
Kitty [74]

Answer:

<em>B</em><em>.</em><em> </em><em>Kinetic</em><em> </em><em>friction</em><em> </em>

Explanation:

This is definitely the correct answer because kinetic friction acts when an object is in motion and it allows the object to move without slipping, etc

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6 0
3 years ago
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a person expended 500 newtons to move a full wheelbarrow 30 meters how much work was done? a person expended 500 newtons to move
stiv31 [10]
<span>A person expended 500 newtons to move a full wheelbarrow 30 meters how much work was done?

</span>In physics, a force is said to do work<span> if, when acting, there is a displacement of the point of application in the direction of the force. The work done would be calculated as follows:
</span>
W = F x d = 500 N (30 m) = 15000 J or 15 kJ
6 0
3 years ago
Four hundred seventy joules of heat are removed from a heat reservoir at a temperature of 470 K. What is the entropy change of t
11111nata11111 [884]

Answer:

ΔS= -1 J/K

Explanation:

Given data

Heat Q= -470J

Temperature T=470 K

To find

Entropy change ΔS

Solution

We know that the entropy change of system is ΔS is given by

ΔS=Q/T

We have take heat value Q as negative because the heat is removed from heat reservoir

So

ΔS=(-470J/470K)

ΔS= -1 J/K

8 0
3 years ago
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A sky diver jumps out of a plane 4000 meters in the air. How fast would he
ddd [48]

Answer:

100 miles per hour

Explanation:

3 0
4 years ago
Calculate: a student lifts an apple to a height of 1 m. The apple weighs 1 N. How much work does the student do on the apple? Ty
Elina [12.6K]

Answer:

1J

Explanation:

Work done = force × distance

1 × 1 = 1

Work done = 1J

J = Joules

6 0
2 years ago
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