Select all that apply.
2 answers:
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Answer:
v = 29.4 m / s
Explanation:
For this exercise we can use the conservation of mechanical energy
Lowest starting point.
Em₀ = K = ½ m v²
final point. Higher
= U = m g h
Let's use trigonometry to lock her up
cos 60 = y / L
y = L cos 60
Height is the initial length minus the length at the maximum angle
h = L - L cos 60
h = L (1- cos 60)
energy is conserved
Em₀ = Em_{f}
½ m v² = mgL (1 - cos 60)
v = 2g L (1- cos 60)
let's calculate
v² = 2 9.8 3.0 (1- cos 60)
v = 29.4 m / s
1) The distance travelled by the electron is
2) The time taken is
Explanation:
1)
The electron in this problem is moving by uniformly accelerated motion (constant acceleration), so we can use the following suvat equation
where
v is the final velocity
u is the initial velocity
a is the acceleration
s is the distance travelled
For the electron in this problem,
is the initial velocity
v = 0 is the final velocity (it comes to a stop)
is the acceleration
Solving for s, we find the distance travelled:
2)
The total time taken for the electron in its motion can also be found by using another suvat equation:
where
v is the final velocity
u is the initial velocity
a is the acceleration
t is the time taken
Here we have
v = 0
And solving for t, we find the time taken:
Learn more about accelerated motion:
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