(a) The work done by the person is 18.83465 kJ.
(b) The average power performed by the person during the walk is 51.4 W.
(c) The amount of food calories burnt is 4.5 Cal.
<h3>Work done by the person</h3>
The work done by the person is calculated as follows;
W = Fd
W = mgh
W = (89.2 x 9.8) x (0.162 x 133)
W = 18,834.65 J
W = 18.83465 kJ
<h3>Average power of the person</h3>
P = Fv
where;
v = (d)/t
v = (133 x 0.162)/(6 x 60 + 6)
v = (133 x 0.162)/(366)
v = 0.0588 m/s
P = (89.2 x 9.8) x 0.0588
P = 51.4 W
<h3>Amount of food calories burnt</h3>
4.1868 kJ = 1 Cal
18.83465 kJ = ?
= 4.5 Cal
Learn more about work done here: brainly.com/question/8119756
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Answer:
Hope this helps
Explanation:
As we know our atmosphere or air have different levels. Every level has other gasses, and every gas has another permeability. when the light comes from lower permeability to higher permeability, it changes its direction. so that means that when the light comes from the moon to the earth, it changes it's direction many more times. it basically means that the shape of the light part of the moon is changed on the earth.
Answer:
Dont know if this is right but i say C
Explanation:
The question is incomplete. Here is the complete question.
Three crtaes with various contents are pulled by a force Fpull=3615N across a horizontal, frictionless roller-conveyor system.The group pf boxes accelerates at 1.516m/s2 to the right. Between each adjacent pair of boxes is a force meter that measures the magnitude of the tension in the connecting rope. Between the box of mass m1 and the box of mass m2, the force meter reads F12=1387N. Between the box of mass m2 and box of mass m3, the force meter reads F23=2304N. Assume that the ropes and force meters are massless.
(a) What is the total mass of the three boxes?
(b) What is the mass of each box?
Answer: (a) Total mass = 2384.5kg;
(b) m1 = 915kg;
m2 = 605kg;
m3 = 864.5kg;
Explanation: The image of the boxes is described in the picture below.
(a) The system is moving at a constant acceleration and with a force Fpull. Using Newton's 2nd Law:




Total mass of the system of boxes is 2384.5kg.
(b) For each mass, analyse each box and make them each a free-body diagram.
<u>For </u>
<u>:</u>
The only force acting On the
box is force of tension between 1 and 2 and as all the system is moving at a same acceleration.


= 915kg
<u>For </u>
<u>:</u>
There are two forces acting on
: tension caused by box 1 and tension caused by box 3. Positive referential is to the right (because it's the movement's direction), so force caused by 1 is opposing force caused by 3:


= 605kg
<u>For </u>
<u>:</u>


= 864.5kg
Technically, both B and D are correct when transmitted through solids, but your answer (and the answer I got from taking the test) will be
D) Longitudinal
Hope this helps!