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leva [86]
3 years ago
10

A stone is dropped from rest from the top of a cliff into a pond below. If its initial height is 10 m, what is its speed when it

hits the water?
Physics
1 answer:
Brut [27]3 years ago
8 0

Answer:

14 m/s

Explanation:

The motion of the stone is a free fall motion, so an accelerated motion with constant acceleration g = 9.8 m/s^2 towards the ground. So, we can use the following SUVAT equation:

v^2 -u^2 = 2gh

where

v is the final speed of the stone as it reaches the water

u = 0 is the initial speed

g = 9.8 m/s^2 is the acceleration

h = 10 m is the distance covered by the stone

Solving for v, we find

v=\sqrt{u^2+2gh}=\sqrt{0+2(9.8 m/s^2)(10 m)}=14 m/s

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A 20.0-N weight slides down a rough inclined plane which makes an angle of 30 degree with the horizontal. The weight starts from
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Answer:

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The force balance of the system is

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