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Blababa [14]
3 years ago
14

Who proposed the "Law of Octaves" for organizing events?

Chemistry
1 answer:
djyliett [7]3 years ago
5 0

b

Explanation:

February 7, 1863, was the day John Newlands published a paper outlining what would be known as “The Law of Octaves”. Newlands discovered if he ordered the known elements by increasing atomic weight, the chemical properties of the elements would be similar for every eighth group

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Which of the following series of scientific steps is most likely in the correct order?
Leni [432]
Observation, hypothesis, experiment is the correct answer
4 0
3 years ago
Read 2 more answers
1. (NH)2CrO-
Alex777 [14]

Question:

1. (NH)2CrO

a) Number of moles of H:

b) Number of moles of N:

Answer:

a) Number of moles of H: 2

b) Number of moles of N: 2

Explanation:

The  (NH)_2CrO is ammonium Chromate which is monoclinic and yellow Crystal that is formed due to the reaction of ammonium Hydroxide and ammonium di-chromate. It is used as catalyst, corrosion inhibitor as well as analytical inhibitors.

Question:

2. Ag.SO.

a) Molar Mass:

b) Percent Composition of Ag:

c) Percent Composition of S:

d) Percent Composition of O:​

Answer:

a) Molar Mass:   155.93 Kg

b) Percent Composition of Ag:   69%

c) Percent Composition of S:  20.5%

d) Percent Composition of O:​ 10.2%

Explanation:

Molar mass =   molar mass of Ag +  molar mass of S +  molar mass of O  

=>107.87+32.06+16

=> 155.93 Kg

Percent Composition of Ag

= \frac{ \text{mass due  to Ag}}{\text {total molar mass}}  \times 100

= \frac{107.87}{155.93} \times 100

= 0.69 \times 100

= 69%

Percent Composition of S:

= \frac{ \text{mass due  to S}}{\text {total molar mass}}  \times 100

=\frac{32.06}{155.93} \times 100

= 0.205 \times 100

= 20.5%

Percent Composition of O:

= \frac{ \text{mass due  to O}}{\text {total molar mass}}  \times 100

= \frac{16.00}{155.93} \times 100

= 0.102 \times 100

= 10.2%

3 0
3 years ago
1. Write formulas for the following compounds:
zhuklara [117]

Answer:

See below.

Explanation:

1) a.

MgCl₂

MgBr₂

Mg(O-H)₂

MgS

b.

CaCl₂

CaBr₂

Ca(O-H)₂

CaO

Ca(C≡N)₂

CaS

2) a.

NaOH

NaC≡N

b.

NH₄C≡N

c.

BaCl₂

Ba(OH)₂

Ba(C≡N)₂

BaO

BaS

7 0
2 years ago
Read 2 more answers
What is the hybridization of the central atom in CO2? Hybridization = What are the approximate bond angles in this substance? Bo
const2013 [10]

Answer:

sp

Explanation:

Hybridization is the combination of atomic orbitals to yield equivalent hybrid orbitals of appropriate energy which can participate in bonding.

In every compound there is a central atom. The central atom is usually the least electronegative atom in the molecule. In this case the least electronegative atom in the molecule is carbon.

The bond between carbon and oxygen in CO2 is intermittent between a pure double and a pure triple bond. Hence, carbon is sp hybridized.

7 0
3 years ago
Determine the empirical formula for a compound that is found to contain
Sphinxa [80]

Answer:

The empirical formula is PCl3

Explanation:

Mass of P is 30.97 g, thus 1.523 g of P equivalent to 0.05 moles of P

Mass of Cl is 35.45 g, thus 5.228 g of Cl equivalent to 0.15 moles of Cl

Therefore moles of P : moles of Cl = 0.05:0.15 = 1:3

Therefore the empirical formula, PCl3

7 0
3 years ago
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