All categories

3 years ago

CuCl2 + Al ---> AlCl3 + Cu

Chemistry

2 answers:

Ket [755]3 years ago

5 0

For a balance chemical equation:

The number of atoms of a molecule should remain conserved that is total number of atom of a molecule in reactant side should equal to the number of atoms of a molecule in the product side.

Here also the number of atoms of an element should remain conserved on both sides, So the answer is option B.

That is

B) 3CuCl₂ + 2Al ---> 2AlCl₃ + 3Cu

Here the number of atoms of Cu, Cl and Al are equal in both side , reactant as well as product.

faust18 [17]3 years ago

3 0

B
All the elements have the same amount of atoms.

You might be interested in

Describe how calcium and fluorine bond together to form calcium fluoride

monitta

Answer: A transfer of electrons occurs when fluorine and calcium react to form an ionic compound. This is because calcium is in group two and so forms ions with a two positive charge. ... A pairs of shared electrons makes one covalent bond. The compound formed is known as a molecule***

5 0

2 years ago

Read 2 more answers

Match the following terms with their definitions:

Burka [1]

Word-Definition

Pure substance- 4
Matter- 2
Atom- 1
Molecule- 3
Element- 5

4 0

3 years ago

When developing an experimental design, which action would improve the

11111nata11111 [884]

Answer:

Explanation:

I'm right I took the test

4 0

2 years ago

Calculate the % Oxygen in NaHCO3

Alexxx [7]

Answer:

Molar mass of NaHCO3 = 84.00661 g/mo

Explanation:

This compound is also known as Baking Soda or Sodium Bicarbonate.

Convert grams NaHCO3 to moles or moles NaHCO3 to grams

Molecular weight calculation:

22.98977 + 1.00794 + 12.0107 + 15.9994*3

3 0

3 years ago

Write the isotopic symbol for the following (show your work) a) An isotope of iodine whose atoms have 78 neutrons b) An isotope

morpeh [17]

Answer:

For a: The isotopic representation of iodine is $_{53}^{131}\textrm{I}$

For b: The isotopic representation of cesium is $_{55}^{137}\textrm{Cs}$

For c: The isotopic representation of strontium is $_{38}^{52}\textrm{Sr}$

Explanation:

The isotopic representation of an atom is: $_Z^A\textrm{X}$

where,

Z = Atomic number of the atom

A = Mass number of the atom

X = Symbol of the atom

For a:

We are given:

Number of neutrons = 78

Atomic number of iodine = 53 = Number of protons

Mass number = 53 + 78 = 131

Thus, the isotopic representation of iodine is $_{53}^{131}\textrm{I}$

For b:

We are given:

Number of neutrons = 82

Atomic number of cesium = 55 = Number of protons

Mass number = 55 + 82 = 137

Thus, the isotopic representation of cesium is $_{55}^{137}\textrm{Cs}$

For c:

We are given:

Number of neutrons = 52

Atomic number of strontium = 38 = Number of protons

Mass number = 38 + 52 = 90

Thus, the isotopic representation of strontium is $_{38}^{52}\textrm{Sr}$

3 0

3 years ago