Answer : The enthalpy change for the reaction is 1043 kJ/mol.
Explanation :
The given chemical reaction is:
As we know that:
The enthalpy change of reaction = E(bonds broken) - E(bonds formed)
![\Delta H=[(2\times B.E_{C\equiv O})+(1\times B.E_{O\equiv O})]-[2\times B.E_{C=O}]](https://tex.z-dn.net/?f=%5CDelta%20H%3D%5B%282%5Ctimes%20B.E_%7BC%5Cequiv%20O%7D%29%2B%281%5Ctimes%20B.E_%7BO%5Cequiv%20O%7D%29%5D-%5B2%5Ctimes%20B.E_%7BC%3DO%7D%5D)
Given:
= 1074 kJ/mol
= 499 kJ/mol
= 802 kJ/mol
Now put all the given values in the above expression, we get:
![\Delta H=[(2\times 1074kJ/mol)+(1\times 499kJ/mol)]-[2\times 802kJ/mol]](https://tex.z-dn.net/?f=%5CDelta%20H%3D%5B%282%5Ctimes%201074kJ%2Fmol%29%2B%281%5Ctimes%20499kJ%2Fmol%29%5D-%5B2%5Ctimes%20802kJ%2Fmol%5D)
Therefore, the enthalpy change for the reaction is 1043 kJ/mol.
Answer: 17.9 joules
Explanation:
The quantity of Heat Energy (Q) required to heat solid silver depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)
Thus, Q = MCΦ
Given that,
Q = ?
Mass= 3.02g
C = 0.24J/g°C
Φ = (Final temperature - Initial temperature)
= 47°C - 22.3°C = 24.7°C
Then, Q = MCΦ
Q = 3.02g x 0.240J/g°C x 24.7°C
Q = 17.9 Joules
Thus, 17.9 joules of heat isrequired.
Decomposition is the reverse of combination. therefore decomposition reaction is a type of reaction where one reactants produces two or more reactants.
Answer: It's the anode broski (B)
Explanation: I'm taking the Chem summer course too broski, this was the correct answer. Cheers broski
Answer:
NH3 Ammonia
Explanation:
Ammonia has 4 regions of electron density around the central nitrogen atom (3 bonds and one lone pair). These are arranged in a tetrahedral shape. The resulting molecular shape is trigonal pyramidal with H-N-H angles of 106.7°.
