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iris [78.8K]
2 years ago
14

The answers to the Lab: Calorimetry and Specific Heat

Chemistry
2 answers:
In-s [12.5K]2 years ago
5 0
The answers to the Lab: Calorimetry and Specific Heat
step3:
aluminum- 11.98
copper-12.14
iron- 12.31
lead- 12.46
step5: 12.46, 52.31, 39.85
step7: 100, 22.4, 27.1, 4.7, 72.9
step5: 12.26, 52.49, 40.13
step7: 100, 22.7, 24.6, 1.9, 75.4
step5: 12.42, 52.66, 40.24
step7: 100, 22.5, 24.9, 2.4,75.1
step5: 12.34, 51.99, 39.65
step7: 100, 22.6, 23.3, 0.7, 76.7
step8: 0.90,0.35,0.44,0.12
cricket20 [7]2 years ago
4 0

Answer:

step3:

aluminum- 11.98

copper-12.14

iron- 12.31

lead- 12.46

step5: 12.46, 52.31, 39.85

step7: 100, 22.4, 27.1, 4.7, 72.9

step5: 12.26, 52.49, 40.13

step7: 100, 22.7, 24.6, 1.9, 75.4

step5: 12.42, 52.66, 40.24

step7: 100, 22.5, 24.9, 2.4,75.1

step5: 12.34, 51.99, 39.65

step7: 100, 22.6, 23.3, 0.7, 76.7

step8: 0.90,0.35,0.44,0.12

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How many molecules of CF₂Cl₂ are in 45.7 grams of CF₂Cl₂? (Show work)
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Answer:

The answer to your question is: 2.20 x 10 ²³ molecules

Explanation:

Data

mass = 45.7 g

molecules of CF₂Cl₂ = ?

Process

1.- Calculate the mass number of CF₂Cl₂

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   total = 12 + 38 + 71

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2.- Use the Avogradro's number to solve the problem

                       121 g -------------------  6.023 x 10²³ molecules of CF₂Cl₂

                        45.7 g ---------------     x

                        x = (45.7 x 6.023 x 10²³) / 121

                        x = 2.75 x 10²⁵ / 121

                        x = 2.20 x 10 ²³ molecules

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