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vampirchik [111]
2 years ago
13

Do bases react with metals the same way that acids do?.

Chemistry
1 answer:
mina [271]2 years ago
6 0

Answer:

Bases do not react with metals in the way that acids do

Explanation:

hope this helps

pls mark brainliest

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Answer:3

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An unknown gas Q requires 2.67 times as long to effuse under the same conditions as the same amount of nitrogen gas. What is the
Misha Larkins [42]

Answer:

The correct answer is 199.66 grams per mole.

Explanation:

Based on law of effusion given by Graham, a gas rate of effusion is contrariwise proportionate to the square root of molecular mass, that is, rate of effusion of gas is inversely proportional to the square root of mass. Therefore,  

R1/R2 = √ M2/√ M1

Here rate is the rate of effusion of the gas expressed in terms of number of mole per uni time or volume, and M is the molecular mass of the gas.  

Rate Q/Rate N2 = √M of N2/ √M of Q

The molecular mass of N2 or nitrogen gas is 28 grams per mole and M of Q is molecular mass of Q and based on the question Q needs 2.67 times more to effuse in comparison to nitrogen gas, therefore, rate of Q = rate of N2/2.67

Now putting the values we get,  

rate of N2/2.67/rate of N2 = √28/ √M of Q

√M of Q = √ 28 × 2.67

M of Q = (√ 28 × 2.67)²

M of Q = 199.66 grams per mole

3 0
3 years ago
What evidence supports the law of conservation of energy?
Travka [436]

Answer:

light energy is converted to chemical energy during photosynthesis.

Explanation:

Law of conservation of energy says: Energy can neither be created nor destroyed-only converted from one form of energy to another.

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What is the total number of valence electrons in the lewis structure of xeo4?
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How much heat is released when you condense 93.9 g of water vapor? <br><br> Show work please ❤️
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<u>Answer:</u>

211.9 J

<u>Explanation:</u>

The molecules of water release heat during the transition of water vapor to liquid water, but the temperature of the water does not change with it.

The amount of heat released can be represented by the formula:

Q=mL_e

where Q = heat energy, m = mass of water and L = latent heat of evaporation.

The latent heat of evaporation for water is L=2257 kJ/kg and the mass of the water is m=93.9 g=0.0939 kg.

The amount of heat released in this process is:

Q=mL_e = (0.0939kg)(2257 kJ/kg)= 211.9 J

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3 years ago
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