Answer:
There were 7 small boxes and 14 large boxes shipped.
Step-by-step explanation:
This problem may be solved by a system of equations:
I am going to say that:
x is the number of small boxes used
y is the number of large boxes used
There were twice as many large boxes shipped as small boxes shipped
This means that 
Each small box of paper weighs 45 pounds and each large box of paper weighs 80 pounds. The total weight of all boxes was 1435 pounds.
This means that 
So we have to solve the following system:
There were 7 small boxes and 14 large boxes shipped.
Answer:
it's 30
Step-by-step explanation:
30+4_2= dakukabilat
I would help but i don’t see a figure
The question is slightly weird.
You have a piece of line, and its ends are 'P' and 'Q'.
All of the points on the paper that are the same distance
from 'P' and 'Q' are the points that form the line that bisects
segment-PQ and is perpendicular to it.
Other words: The line that is perpendicular to PQ at its mid-point.
Other words: The perpendicular bisector of segment PQ.
All of the points in space that are the same distance from
'P' and 'Q' are the points that form the plane perpendicular
to segment PQ at its mid-point.
Answer:
the modulus of a complex number z = a + bi is:
Izl= √(a²+b²)
The fact that n is complex does not mean that n doesn't has a real part, so we must write our numbers as:
m = 2 + 6i
n = a + bi
Im + nl = 3√10
√(a² + b²+ 2²+ 6²)= 3√10
√(a^2 + b^2 + 40) = 3√10
squaring both side
a²+b²+40 = 3^2*10 = 9*10 =90
a²+b²= 90 - 40
a²+b²=50
So,
|n|=√(a^2 + b^2) = √50
The modulus of n must be equal to the square root of 50.
now
values a and b such
a^2 + b^2 = 50.
for example, a = 5 and b = 5
5²+5²=25+25= 50
Then a possible value for n is:
n = 5+5i
