Answer:
False
Explanation:
The statement ; Regardless of any concentration of ammonium solution the precipitate of unknown halide after 0.1M AgNO3 will remain is FALSE
This is Because the remaining concentration of AgNO3 is dependent on the solubility of Ag⁺
<span>52.7 ml
First, determine how many moles of NaCl you have
Atomic weight sodium = 22.989769
Atomic weight chlorine = 35.453
Molar mass NaCl = 22.989769 + 35.453 = 58.442769 g/mol
Moles NaCl = 15.4 g / 58.442769 g/mol = 0.263505653 mol
Now molarity is defined as moles/liter, so let's set up an equation for the number of liters we can make.
molarity = moles/liter
Substitute the known values
5.00 = 0.263505653/liter
And solve for liters
5.00 = 0.263505653/liter
5.00* liter = 0.263505653
liter = 0.263505653/5.00
liter = 0.052701131
So you can make 0.0527 liters of the solution. Or 52.7 ml</span>
Explanation:
White precipitate of silver chloride get dissolves in excess ammonia to formation of complex between silver ions, chloride ions and ammonia molecules.
The chemical reaction is given as:
![AgCl(s)+2NH_3(aq)\rightarrow Ag[(NH_3)_2]^+Cl^-(aq)](https://tex.z-dn.net/?f=AgCl%28s%29%2B2NH_3%28aq%29%5Crightarrow%20Ag%5B%28NH_3%29_2%5D%5E%2BCl%5E-%28aq%29)
When 1 mole of silver chloride is added to 2 mole of an aqueous ammonia it form coordination complex of diaaminesilver(I) chloride.
speed of light=wavelength*frequency
3*10^8m/s=wavelength*1.20*10^13
wavelength=3*10^8/1.2*10^13
=10^-5/0.4=2.5*10^-5m
