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Andreyy89
3 years ago
9

the melting point of scandium fluoride is 1552°c, explain why scandium fluoride has a high melting point.​

Chemistry
2 answers:
Greeley [361]3 years ago
5 0

Answer:

Scandium(III) fluoride, ScF3, is an ionic compound. It is slightly soluble in water but dissolves in the presence of excess fluoride to form the ScF63− anion.

hope it will help you......

pogonyaev3 years ago
4 0

Answer:

yes the above answer is right

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When a hydrochloric acid solution is combined with a potassium hydroxide solution, an acid-base reaction occurs. write a balance
Verizon [17]

Answer:

HCl(aq) + KOH(aq) ⇒ KCl(aq) + H₂O(l)

Explanation:

Hydrochloric acid is an acid because it releases H⁺ in an aqueous solution.

Potassium hydroxide is a base because it releases OH⁻ in an aqueous solution.

When an acid reacts with a base they form a salt and water. This is a neutralization reaction. The neutralization reaction between hydrochloric acid and potassium hydroxide is:

HCl(aq) + KOH(aq) ⇒ KCl(aq) + H₂O(l)

5 0
2 years ago
Which statement best relates the strength and concentration of a base? At high enough concentrations, a weak base becomes strong
Lorico [155]

Answer: Option (b) is the correct answer.

Explanation:

When there are more number of hydroxide ions in a solution then there will be high concentration of OH^{-} or hydroxide ions. As a result, more will be the strength of base in that particular solution.

A base is strong when it readily dissociate into its ions in the solution. When a base is strong, then it does not matter at what concentration it is dissolved in the solution because despite of its low concentration it will remain a strong base.

Thus, we can conclude that out of the given options, the statement even at low concentrations, a strong base is strong best relates the strength and concentration of a base.


6 0
3 years ago
Read 2 more answers
A study of the decomposition reaction 3RS2  3R + 6S yields the following initial rate dat
shutvik [7]
Missing question: What is the rate constant for the reaction?
<span>[RS2](mol L-1) Rate (mol/(L·s))
0.150                0.0394
0.250                0.109
0.350                0.214
0.500                0.438</span>
Chemical reaction: 3RS₂ → 3R + 6S.
Compare second and fourth experiment, when concentration is doubled, rate of concentration is increaced by four. So rate is:
rate = k·[RS₂]².
k = 0,438 ÷ (0,500)².
k = 1,75 L/mol·s.
3 0
3 years ago
More help please!?!?!?!?!
e-lub [12.9K]
It's back wards lol you need to take it right
6 0
3 years ago
Read 2 more answers
How much heat is released when 1.4 mol of hydrogen fluoride are produced? H2(g) +F2(g) → 2HF(g) +536kJ (Please show work)
polet [3.4K]

Answer:

375.2 kJ

Explanation:

  • H₂(g) +F₂(g) → 2HF(g) +536kJ

The information the equation above provides lets us know that when 2 mol of hydrogen fluoride (HF) are produced, 536 kJ of energy (as heat) is produced.

We can then <u>state a rule of three</u>:

  • 2 mol HF --------  536 kJ
  • 1.4 mol HF --------- X

And <u>solve for X</u>:

  • X = 1.4 mol * 536 kJ / 2 mol
  • X = 375.2 kJ
7 0
3 years ago
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