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EleoNora [17]
2 years ago
5

Hugo began his science experiment with 22 grams of sugar crystals. During the experiment, the change in the mass of the sugar cr

ystals was
6 grams.
What is the final mass of the sugar crystals?
Mathematics
1 answer:
fgiga [73]2 years ago
6 0

Answer:

I don't think there's enough information here to answer your question

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SERIOUSLY NEED HELP WITH THIS QUESTION.
Ann [662]
The answer is 1000 cubic feet either. The reason for that is fallowing:
Imagine you cut cube 2 peaces so that your cut is normal to bases and it passes throught both bases. If you take those 2 pieces and switch their position and stick one to another you will get non tilted original cube.

what you can conclude from this is that tilting doesnt influence volume if bases and height remain the same.
3 0
3 years ago
Read 2 more answers
The width of a rectangular garden is 4.5 meters shorter than its length which is x meters.
Contact [7]

Answer:

  A.  width = x - 4.5

  B.  111 = 2(x + (x -4.5))

Step-by-step explanation:

A. The width is 4.5 meters shorter than x, so is x -4.5.

__

B. The perimeter is twice the sum of length and width. It is 111 meters, so an equation for it could be ...

  111 = 2(x + (x -4.5))

4 0
3 years ago
Greatest to least 0.386;0.3;0.683;0.836
levacccp [35]
<span>Here you go .. ordered as you wish ..
0.836
</span><span>0.683
</span><span>0.386
</span><span>0.3</span>
6 0
3 years ago
2/3q = 1/2 what does q equal as a decimal
goldfiish [28.3K]
Is that 2/3 of q or 2 over 3q?
for 2/3 of q. q=1/2 x 3/2 =3/4=0.75

for 2 over 3q q = 2 x 2/3= 4/3=1.3333
3 0
3 years ago
HELP!!!!
aniked [119]

Answer:

A. Plane B because it was 9.33 miles away

B. 48 units

Step-by-step explanation:

A. Since the airplanes fly at an angle to the runway, their direction forms a triangle with the runway with their height above the ground as the opposite of the angle and their distance from the airport as the hypotenuse.

So for airplane A with 44° angle of departure,

sin44° = y/h where y = height above the ground and h = distance from airport

So h = y/sin44° = 6/sin44° = 8.64 miles

So for airplane B with 40° angle of departure,

sin40° = y/H where y = height above the ground and H = distance from airport

So H = y/sin40° = 6/sin40° = 9.33 miles

Since airplane B is at 9.33 miles away from the airport whereas airplane A is 8.64 miles from the airport, airplane B is farther away.

B. We know that scale factor = new size/original size

Our scale factor = 4 and original size = 12 units. So,

new size = scale factor original size = 4 × 12 = 48 units.

8 0
3 years ago
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