Answer:
C. The water particles move up through the wave.
Lead(II) nitrate will react with iron(III) chloride to produce the precipitate lead(II) chloride as shown in the balanced reaction
2FeCl3(aq) + 3Pb(NO3)2(aq) → 2Fe(NO3)3(aq) + 3PbCl2(s)
Calculating the amount of the precipitate lead(II) chloride each reactant will produce:
mol PbCl2 = 0.050L Pb(NO3)2 (0.100mol/1L)(3mol PbCl2/3mol Pb(NO3)2)
= 0.00500mol PbCl2
mol PbCl2 = 0.050L FeCl3 (0.100mol FeCl3/1L)(3mol PbCl2/2mol FeCl3) = 0.00750mol PbCl2
The reactant Pb(NO3)2 produces a lesser amount of the precipitate PbCl2, therefore, the lead(II) nitrate is the limiting reagent for this reaction.
Answer:
Hydrogen Fluoride will dissolve glass & eat concrete; BUT mixed with water, it is very nasty - but fairly weak!
A strong acid EASILY donates a Proton (H+).
Look up dissociation of acids and the ones that give up that H+ is the strong one.
Explanation:
It should be A)It lost a neutron.
Hey there!
D = m / V
13.6 = 76.2 / V
V = 76.2 / 13.6
V = 5.602 mL